2

我是窗口应用程序的新手。
我编写了一个代码来读取文件夹内的文件并逐行读取并找到一些字符串并将其计数显示给dataGridView。

我想填充一个不起作用的 dataGridview。
我在互联网上尝试了不同的方法，但都没有奏效。

我知道我可能会犯一个愚蠢的错误。
我的代码如下

  public class FileDetail
    {
        public  string filename;
        public int openConnectionCount;
        public int closeConnectionCount;
    }


    private void button1_Click(object sender, EventArgs e)
    {
        int openConnectionCount = 0;
        int closeConnectionCount = 0;
        List<FileDetail> fileDetails =new List<FileDetail>();
        foreach (string file in Directory.EnumerateFiles(textBox1.Text, "*.*", SearchOption.AllDirectories))
        {
            FileDetail fileDetail =new FileDetail();
            fileDetail.filename = file;
            // Read the file as one string.
            using (StreamReader myFile = new StreamReader(file))
            {

                string line;
                while ((line = myFile.ReadLine()) != null)
                {
                    if (line.Contains(" OpenConnection()")) openConnectionCount++;
                    if (line.Contains(" CloseConnection()")) closeConnectionCount++;
                }
                fileDetail.openConnectionCount = openConnectionCount;
                fileDetail.closeConnectionCount = closeConnectionCount;
            }
            fileDetails.Add(fileDetail);
            openConnectionCount = 0;
            closeConnectionCount = 0;
        }



        dataGridView1.AutoGenerateColumns = false;

        dataGridView1.Columns.Add("filename", "File Name");
        dataGridView1.Columns.Add("openConnectionCount", "Open Connection");
        dataGridView1.Columns.Add("closeConnectionCount", "close Connection");

        dataGridView1.Columns[0].DataPropertyName = "filename";
        dataGridView1.Columns[1].DataPropertyName = "openConnectionCount";
        dataGridView1.Columns[2].DataPropertyName = "closeConnectionCount";

        var filenamesList = new BindingList<FileDetail>(fileDetails); // <-- BindingList
        dataGridView1.DataSource = filenamesList;


        //dataGridView1.DataSource = fileDetails;




        //dataGridView1.b

        //foreach (var fileDetail in fileDetails)
        //{
        //    label1.Text += "FileName:=" + fileDetail.filename + "\t Open Connection:= " +
        //                   fileDetail.openConnectionCount + "\t close connection:=" +
        //                   fileDetail.closeConnectionCount+"\n";
        //}
    }

编辑：-

我已经关注了一些相同的链接
如何将列表绑定到dataGridView？
http://social.msdn.microsoft.com/Forums/eu/csharplanguage/thread/766c7b46-6431-4ec1-8e74-50f718c6606b

4

2 回答 2

8

数据绑定仅适用于设置/获取属性，不适用于公共字段。

试着改变你的FileDetail样子：

public class FileDetail
{
    public  string filename { get; set; }
    public int openConnectionCount { get; set; }
    public int closeConnectionCount { get; set; }
}
于 2013-01-18T07:19:03.300 回答
1

如果要自动生成 datagridview 列，则可以将其用作

public class FileDetail
{
    [DisplayName("File Name")]    
    public  string filename { get; set; }
    [DisplayName("Open Connection")]    
    public int openConnectionCount { get; set; }
    [DisplayName("close Connection")]    
    public int closeConnectionCount { get; set; }
}

更多您可以将列表用作数据源而无需绑定源作为

dataGridView1.DataSource = fileDetails.ToArray();

有关更多信息，您可以查看此链接 Bind List of Class objects as Datasource to DataGridView

于 2013-12-21T05:10:38.843 回答