java - 如何以毫秒为单位将日期转换为数据库中的日期？

Question

我有一个@Entitywith 字段

    @Temporal(TemporalType.TIMESTAMP)
    @Column(name = "created_on", nullable = false)
    private Date createdOn;

将时间戳保存为

+----+------+------------+-------+--------------------------+---------------------+---------------------+------+
| id | name | type       | units | description              | created_on          | retired_on          | core |
+----+------+------------+-------+--------------------------+---------------------+---------------------+------+
|  1 | v1   | Double     | u1    | created via migration    | 2013-01-14 13:15:19 | NULL                |    1 |
|  2 | v2   | String     | u2    | created via migration    | 2013-01-14 13:15:19 | NULL                |    1 |
|  3 | v3   | BigDecimal | u3    | created via migration    | 2013-01-14 13:15:19 | NULL                |    0 |
| 27 | v4   | String     | u4    | created with web service | 2013-01-15 10:37:30 | 2013-01-15 11:27:48 |    1 |
+----+------+------------+-------+--------------------------+---------------------+---------------------+------+

当我检索数据时，我得到 Date 对象，其值如下

"createdOn": 1358198119000,
"createdOn": 1358198119000,
"createdOn": 1358198119000,
"createdOn": 1358275050000, 

如何将它们转换回带有时间戳'2013-01-15 10:37:30'的日期，而不是数字1358198119000？

Answer 1

这个值只是自纪元以来的毫秒数，它们仍然代表正确的Date对象。你的“时间戳”意味着什么？作为Timestampjava 类实例或只是有效格式化？

像这样的东西可以帮助回答是的第一个问题：

java.sql.Timestamp timestamp = new java.sql.Timestamp(createdOn.getTime());

像这样的东西可以帮助回答“是”的第二个问题：

SimpleDateFormat formater = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String timestampedDate = formater.format(createdOn);

Answer 2

将您的 TemporalType 更改为 DATE

@Temporal(TemporalType.DATE)
@Column(name = "created_on", nullable = false)
private Date createdOn;