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可能重复：
如何获取查询字符串值？

我有以下查询字符串：

"active_tab=delivered&active_tab=all&active_tab=delivered&active_tab=outstanding
&active_tab=delivered&active_tab=outstanding&active_tab=all&active_tab=delivered&active_tab=outstanding&title_filter=conformance&title_filter=delivering&title_filter=packaging
&title_filter=delivering&title_filter=all&title_filter=delivering&title_filter=all&title_filter=packaging&title_filter=conformance&title_filter=packaging
&title_filter=delivering&title_filter=packaging&title_filter=ordered"

我将如何解析上述查询字符串中的最终title_filter（“ordered”）和（“delivered”）？active_tab此外，如果该查询字符串变量不存在，则拥有它 =""

4

2 回答 2

4 
var query = {};

var largeString = "active_tab=delivered&active_tab=all&active_tab=delivered&active_tab=outstanding&active_tab=delivered&active_tab=outstanding&active_tab=all&active_tab=delivered&active_tab=outstanding&title_filter=conformance&title_filter=delivering&title_filter=packaging&title_filter=delivering&title_filter=all&title_filter=delivering&title_filter=all&title_filter=packaging&title_filter=conformance&title_filter=packaging&title_filter=delivering&title_filter=packaging&title_filter=ordered";

largeString.split('&').forEach(function(keyValue){
    var kvp = p.split('=');
    query[kvp[0]]= kvp[1];
});

如果您需要支持数组：

largeString.split('&').forEach(function(keyValue){
    var kvp = keyValue.split('=');

    if(kvp[0] in query){
        if(typeof(query[kvp[0]] === 'string')){
            query[kvp[0]] = [query[kvp[0]]];
        }
        query[kvp[0]].push(kvp[1]);
    }else{
        query[kvp[0]] = kvp[1];
    }
});
于 2013-01-17T21:08:16.953 回答
0

我修改了查询字符串以删除重复项，然后我做了：

var active_tab = window.location.search.split('active_tab=')[1].split('&')[0]
var title_filter = window.location.search.split('title_filter=')[1].split('&')[0]
于 2013-01-17T21:20:54.640 回答