我使用 WITH 查询进行了选择,如下所示:
WITH test AS (select id, sum(value) as value from test group by id)
SELECT name, t.value from names JOIN test t ON (t.id = names.id)
但我需要使用 2 个 WITH 查询,有什么办法吗?
我使用 WITH 查询进行了选择,如下所示:
WITH test AS (select id, sum(value) as value from test group by id)
SELECT name, t.value from names JOIN test t ON (t.id = names.id)
但我需要使用 2 个 WITH 查询,有什么办法吗?