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我使用 WITH 查询进行了选择,如下所示:

WITH test AS (select id, sum(value) as value from test group by id)
SELECT name, t.value from names JOIN test t ON (t.id = names.id)

但我需要使用 2 个 WITH 查询,有什么办法吗?

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1 回答 1

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WITH
    name1 AS (SELECT ...),
    name2 AS (SELECT ...)
SELECT ...
于 2013-01-17T19:09:21.900 回答