3

我正在尝试对完全由字符串组成的 CSV 数据进行一些类型转换。我在想我会使用标题名称字典来函数并将这些函数映射到每个 CSV 行。我只是有点坚持如何有效地将多个功能映射到一行。我正在考虑枚举标题并创建一个新的函数索引字典:

header_map = {'Foo':str,
              'Bar':str,
              'FooBar':float}

csv_data = [('Foo', 'Bar', 'FooBar'),
            #lots of data...
           ]

index_map = {}

#enumerate the rows and create a dictionary of index:function
for i, header in enumerate(csv_data[0]):
    index_map[i] = header_map[header]

#retrieve the function for each index and call it on the value
new_csv = [[index_map[i](value) for i, value in enumerate(row)] 
           for row in csv_data[1:]]

我只是好奇是否有人知道完成此类操作的更简单、有效的方法?

4

3 回答 3

1

没有测试(没有样本输入),但这似乎是你想要的:

heads = csv_data[0]
new_csv = heads + [
              tuple(header_map[head](item) for head, item in zip(heads, row))
          for row in csv_data[1:]]
于 2013-01-17T14:00:08.323 回答
1

这是一个方法,using_converter它稍微快一些:

import itertools as IT

header_map = {'Foo':str,
              'Bar':str,
              'FooBar':float}

N = 20000
csv_data = [('Foo', 'Bar', 'FooBar')] + [('Foo', 'Bar', 1123.451)]*N

def original(csv_data):
    index_map = {}
    #enumerate the rows and create a dictionary of index:function
    for i, header in enumerate(csv_data[0]):
        index_map[i] = header_map[header]

    #retrieve the appropriate function for each index and call it on the value
    new_csv = [[index_map[i](value) for i, value in enumerate(row)]
               for row in csv_data[1:]]
    return new_csv

def using_converter(csv_data):
    converters = IT.cycle([header_map[header] for header in csv_data[0]])
    conv = converters.next
    new_csv = [[conv()(item) for item in row] for row in csv_data[1:]]
    return new_csv

def using_header_map(csv_data):
    heads = csv_data[0]
    new_csv = [
        tuple(header_map[head](item) for head, item in zip(heads, row))
        for row in csv_data[1:]]
    return new_csv

# print(original(csv_data))
# print(using_converter(csv_data))
# print(using_header_map(csv_data))

基准测试timeit

原代码:

% python -mtimeit -s'import test' 'test.original(test.csv_data)'
100 loops, best of 3: 17.3 msec per loop

稍快的版本(使用 itertools):

% python -mtimeit -s'import test' 'test.using_converter(test.csv_data)'
100 loops, best of 3: 15.5 msec per loop

列夫·列维茨基的版本:

% python -mtimeit -s'import test' 'test.using_header_map(test.csv_data)'
10 loops, best of 3: 36.2 msec per loop
于 2013-01-17T14:52:10.837 回答
0

如果您知道标题中的标题顺序,则可以使用函数列表而不是 dict,

>>> header = [str, str, float]
>>> csv = [("aaa", "bbb", "3.14")] * 10
>>> map(lambda line: map(lambda f, arg: f(arg), header, line), csv)
[['aaa', 'bbb', 3.14], ['aaa', 'bbb', 3.14], ...
于 2013-01-17T14:09:40.417 回答