4

考虑这张表some_table：

+--------+----------+---------------------+-------+
| id     | other_id | date_value          | value |
+--------+----------+---------------------+-------+
| 1      | 1        | 2011-04-20 21:03:05 | 104   |
| 2      | 1        | 2011-04-20 21:03:04 | 229   |
| 3      | 3        | 2011-04-20 21:03:03 | 130   |
| 4      | 1        | 2011-04-20 21:02:09 | 97    |
| 5      | 2        | 2011-04-20 21:02:08 | 65    |
| 6      | 3        | 2011-04-20 21:02:07 | 101   |
| ...    | ...      | ...                 | ...   |
+--------+----------+---------------------+-------+

我想按 选择和分组other_id，这样我只能得到唯一other_id的 s。此查询有效（信用@MichaelPakhantsov）：

select id, other_id, date_value, value from
 (
   SELECT id, other_id, date_value, value, 
   ROW_NUMBER() OVER (partition by other_id order BY Date_Value desc) r
   FROM some_table 
 )
 where r = 1

我怎样才能得到相同的结果，但要计算每个other_id. 期望的结果如下所示：

+--------+----------+---------------------+-------+-------+
| id     | other_id | date_value          | value | count |
+--------+----------+---------------------+-------+-------+
| 1      | 1        | 2011-04-20 21:03:05 | 104   | 3     |
| 5      | 2        | 2011-04-20 21:02:08 | 65    | 2     |
| 3      | 3        | 2011-04-20 21:03:03 | 130   | 2     |
+--------+----------+---------------------+-------+-------+

我已经尝试COUNT(other_id)在内部和外部选择中使用，但它会产生这个错误：

ORA-00937: 不是单组组函数

注意：类似于此问题（示例表和从那里获取的答案），但该问题没有给出折叠行的计数。

4

1 回答 1

8

添加一个

count(*) OVER (partition by other_id) cnt

到内部查询

select id, other_id, date_value, value, cnt from
 (
   SELECT id, other_id, date_value, value, 
   ROW_NUMBER() OVER (partition by other_id order BY Date_Value desc) r,
   count(*) OVER (partition by other_id) cnt
   FROM some_table 
 )
 where r = 1
于 2013-01-17T11:56:51.460 回答