0

我需要在客户表和订单表之间以 1:N 的关系列出客户表中的列、第一个订单的日期和最后一个订单的所有数据。我正在使用 Oracle 10g。

如何做到这一点的最佳方法？

表客户
---------------
身份证号
名称 VARCHAR2(200)
订阅日期 DATE


表顺序
---------------
身份证号
id_order NUMBER
购买日期 DATE
购买价值 NUMBER
4

4 回答 4

1

这是一种方法，使用row_number函数、一个连接和聚合：

select c.*,
       min(o.purchase_date) as FirstPurchaseDate, 
       min(case when seqnum = 1 then o.id_order end) as Last_IdOrder,
       min(case when seqnum = 1 then o.purchase_date end) as Last_PurchaseDate,
       min(case when seqnum = 1 then o.purchase_value end) as Last_PurchaseValue
from Customer c join
     (select o.*,
             row_number() over (partition by o.id order by purchase_date desc) as seqnum
      from orders o
     ) o
     on c.customer_id = o.order_id
group by c.customer_id, c.name, c.subscribe_date
于 2013-01-16T20:49:20.583 回答
1

如何将customer表连接到表并不明显orders（order是 Oracle 中的保留字，因此您的表无法命名order）。如果我们假设id_orderinorders连接到idincustomer

SELECT c.id customer_id,
       c.name name,
       c.subscribe_date,
       o.first_purchase_date,
       o.id last_order_id,
       o.purchase_date last_order_purchase_date,
       o.purchase_value last_order_purchase_value
  FROM customer c
       JOIN (SELECT o.*,
                    min(o.purchase_date) over (partition by id_order) first_purchase_date,
                    rank() over (partition by id_order order by purchase_date desc) rnk
               FROM orders o) o ON (c.id = o.id_order)
 WHERE rnk = 1
于 2013-01-16T20:49:44.823 回答
0

也许像这样假设表中的ID字段Order实际上是Customer ID：

SELECT C.*, O1.*, O2.purchase_Date as FirstPurchaseDate
FROM Customer C
LEFT JOIN 
(
  SELECT Max(purchase_date) as pdate, id
  FROM Orders
  GROUP BY id
) MaxPurchaseOrder 
  ON C.Id = MaxPurchaseOrder.Id
LEFT JOIN Orders O1 
  ON MaxPurchaseOrder.pdate = O1.purchase_date 
  AND MaxPurchaseOrder.id = O1.id
LEFT JOIN 
(
  SELECT Min(purchase_date) as pdate, id
  FROM Orders
  GROUP BY id
) MinPurchaseOrder 
  ON C.Id = MinPurchaseOrder.Id
LEFT JOIN Orders O2 
  ON MinPurchaseOrder.pdate = O2.purchase_date 
  AND MinPurchaseOrder.id = O2.id

还有sql 小提琴。

于 2013-01-16T20:53:52.477 回答
0

我对您的字段名称感到困惑，但我假设 ORDER.id 是 CUSTOMER 表中的 id。

最早的订单日期很容易。

select CUSTOMER.*, min(ORDER.purchase_date)
from CUSTOMER
  inner join ORDER on CUSTOMER.id = ORDER.id
group by CUSTOMER.*

要获取最后的订单数据，请再次将其连接到 ORDER 表。

select CUSTOMER.*, min(ORD_FIRST.purchase_date), ORD_LAST.*
from CUSTOMER
  inner join ORDER ORD_FIRST on CUSTOMER.id = ORD_FIRST.id
  inner join ORDER ORD_LAST on CUSTOMER.id = ORD_LAST.id
group by CUSTOMER.*, ORD_LAST.*
having ORD_LAST.purchase_date = max(ORD_FIRST.purchase_date)
于 2013-01-16T20:44:57.250 回答