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好吧，澄清一下，pawn 是一种与 C++ 非常相似的语言。我正在编写一个需要位掩码权限（在 php 中）的管理控制面板，我实际上不知道我是否将权限正确转换（因为这是我从未做过的事情）到 PHP。我使用 define() 来定义权限。这是它最初的样子（典当）：

//Pawn
enum EAdminFlags (<<= 1) {
    EAdminFlags_None = 0, 
    EAdminFlags_BasicAdmin = 1, //kick, fine, etc 0
    EAdminFlags_CanGiveGuns, //1
    EAdminFlags_HouseAdmin, //2
    EAdminFlags_IRCAdmin, //3
    EAdminFlags_BusinessAdmin, //4
    EAdminFlags_AdminManage, //5 can see invisible admins/manipulate admin flags
    EAdminFlags_Scripter, //getpvars, reloadcmds, stuff only scripters should need 6
    EAdminFlags_HelperManage, // 7 manage helpers/teachers
    EAdminFlags_Unbannable, //unbanable under ANY circumstances 8
    EAdminFlags_CanRefundSelf, //can refund himself
    EAdminFlags_VehicleAdmin, //10 can manipulate player vehicles
    EAdminFlags_AntiCheat, //immune to the anticheat 11
    EAdminFlags_BigEars, //can /bigears, /bigfamilyears, /bigmouth
    EAdminFlags_SetName, //13
    EAdminFlags_CanHide, //can toggle/untoggle hidden on themselves 14
    EAdminFlags_Invisible, //Invisible on admins list(like 9999s before) 15
    EAdminFlags_GiveDrugs, //server manager, can restart the server/do rcon cmds, create job cars 16
    EAdminFlags_Unban, //can unban, oban, oprison people 17
    EAdminFlags_WeatherManage, //can manage weather/time 18
    EAdminFlags_GiveRestrictedGun, //can give restircted guns 19
    EAdminFlags_TeleportOthers, //can teleport other people 20
    EAdminFlags_CanBanAdmins, //can ban other admins(or any punishments) 21
    EAdminFlags_GiveMats, //can give materials 22
    EAdminFlags_StatsManage, //23 /setstat, /sethp, /setarmor
    EAdminFlags_FamilyAdmin, //24
    EAdminFlags_FactionAdmin, //25
    EAdminFlags_MassCmds, //26 can do /masstphere, /massmoney, /masskick, /massnuke
    EAdminFlags_Nuke, //27 can do things like /nuke, sparta, rangeban
    EAdminFlags_RangeBan, //28 can range ban
    EAdminFlags_GiveMoney, //29 can /givemoney /money
    EAdminFlags_Donations, //30 can give DPS/set donate rank
    EAdminFlags_ServerManager, //can restart the server, etc, use /noooc, /nopms, /nonewb
    EAdminFlags_All = -1,
};

现在这就是我在 PHP 中定义它的方式：

    define("EAdminFlags_None",0);
    define("EAdminFlags_BasicAdmin",1);
    define("EAdminFlags_CanGiveGuns",1 << 0);
    define("EAdminFlags_HouseAdmin",1 << 1);
    define("EAdminFlags_IRCAdmin",1 << 2);
    define("EAdminFlags_BusinessAdmin",1 << 3);
    define("EAdminFlags_AdminManage",1 << 4);
    define("EAdminFlags_Scripter",1 << 5);
    define("EAdminFlags_HelperManage",1 << 6);
    define("EAdminFlags_Unbannable",1 << 7); 
    define("EAdminFlags_CanRefundSelf",1 << 8);
    define("EAdminFlags_VehicleAdmin",1 << 9);
    define("EAdminFlags_AntiCheat",1 << 10);
    define("EAdminFlags_BigEars",1 << 11);
    define("EAdminFlags_SetName",1 << 12);
    define("EAdminFlags_CanHide",1 << 13);
    define("EAdminFlags_Invisible",1 << 14);
    define("EAdminFlags_GiveDrugs",1 << 15);
    define("EAdminFlags_Unban",1 << 16);
    define("EAdminFlags_WeatherManage",1 << 17);
    define("EAdminFlags_GiveRestrictedGun",1 << 18);
    define("EAdminFlags_TeleportOthers",1 << 19);
    define("EAdminFlags_CanBanAdmins",1 << 20);
    define("EAdminFlags_GiveMats",1 << 21);
    define("EAdminFlags_StatsManage",1 << 22);
    define("EAdminFlags_FamilyAdmin",1 << 23);
    define("EAdminFlags_FactionAdmin",1 << 24);
    define("EAdminFlags_MassCmds",1 << 25);
    define("EAdminFlags_Nuke",1 << 26);
    define("EAdminFlags_RangeBan",1 << 27);
    define("EAdminFlags_GiveMoney",1 << 28);
    define("EAdminFlags_Donations",1 << 29);
    define("EAdminFlags_ServerManager",1 << 30);
    define("EAdminFlags_All",-1);

我比较了位标志，大多数时候它只识别EAdminFlags_All权限以及EAdminFlags_None和EAdminFlags_BasicAdmin。所以我在 PHP 中定义它的方式可能存在问题。权限存储在数据库中，并保存为原始整数值，例如：51531777 然后将其加载到 PHP 中并进行比较，如下所示：

$account = new Account(Auth::getUserID());
echo "Welcome ".$account->getUsername()."<br>";
if($account->getAdminPerms(EAdminFlags_FamilyAdmin)) { 
    echo "You are a family admin."; //testing purposes
    //If the person has those permissions set then display he / she is a family admin but even if the permissions are set to EAdminFlags_BasicAdmin, it will still display it wrong
}
public function getAdminLevel() {
    return $this->adminlevel; //This holds the integer value "51531777"
}
public function getAdminPerms($n) {
    return ($this->adminlevel & (1 << $n)) != 0;
}

事先感谢您的帮助，我真的很感激。

4

2 回答 2

1 
define("EAdminFlags_BasicAdmin",1);
define("EAdminFlags_CanGiveGuns",1 << 0);

这两个是等价的……移位 0 基本上是一个空操作，所以“cangiveguns”与 basicadmin 具有相同的值

于 2013-01-16T17:09:52.577 回答
1

假设您对常量的移位操作是正确的，那么您在检测特定权限标志时会出错：

public function getAdminPerms($n) {
    return ($this->adminlevel & (1 << $n)) != 0;
}

输入是标志值，它只是设置在正确位置的 1 位。您再次错误地移位，但您需要做的就是将整数值与从数据库中读取的整数值相加：

public function getAdminPerms($n) {
    return ($this->adminlevel & $n)) != 0;
}

回来的路也是一样的。从零值开始，您可以添加所有管理员权限标志，并对所有常量值进行位或运算，而无需移位：

$newAdmin = EAdminFlags_AntiCheat | EAdminFlags_CanGiveGuns;
于 2013-01-16T17:32:04.300 回答