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尝试使用创建count(*)类型查询时CriteriaBuilder出现以下别名问题。

我应该对下面的代码进行哪些更改才能获得计数？

约束：

  1. 我必须使用 CriteriaBuilder/Query 因为必须根据值动态构建 where 子句。
  2. 我只需要 COUNT，而不需要内存中的对象列表。

代码示例片段：

 Class<ReqStatCumulative> entityClass = ReqStatCumulative.class;
 @Override
    public long getCountForAlertConfig(AlertConfig cfg) {
        long count = 0L;
        if (null != cfg) {
            CriteriaBuilder qb = entityManager.getCriteriaBuilder();

            Metamodel model = entityManager.getMetamodel();
            EntityType<ReqStatCumulative> reqStatEntType_ = model.entity(entityClass);
            CriteriaQuery<ReqStatCumulative> cq = qb.createQuery(entityClass);
            Root<ReqStatCumulative> rootReqStatEnt = cq.from(reqStatEntType_);
            Path<Long> processTimeSeconds = rootReqStatEnt.<Long> get("processTimeSeconds");
            cq.where(qb.and(qb.greaterThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec()),//
                    qb.lessThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec() + 100))//
            );//
            findCountByCriteria(entityManager, cq, qb);
            log.debug("\n\t#####Alert desc:" + cfg.getDescription());
            log.debug("\n\t#####Alert count= " + count);
        } else {
            // Do nothing
        }
        return count;
    }

    public <T> Long findCountByCriteria(EntityManager em, CriteriaQuery<T> cqEntity, CriteriaBuilder qb) {
        CriteriaBuilder builder = qb;
        CriteriaQuery<Long> cqCount = builder.createQuery(Long.class);
        Root<?> entityRoot = cqCount.from(cqEntity.getResultType());
        cqCount.select(builder.count(entityRoot));
        cqCount.where(cqEntity.getRestriction());
        return em.createQuery(cqCount).getSingleResult();
    }

日志：我希望在所有 where 子句属性中使用 generateAlias0 而不是 generateAlias1。

select count(*) from abc.domain.ReqStatCumulative as **generatedAlias0** where ( **generatedAlias1**.processTimeSeconds>5L ) and ( **generatedAlias1**.processTimeSeconds<200L )

10:48:57.169 [main] DEBUG o.h.h.i.ast.QueryTranslatorImpl - parse() - HQL: select count(*) from abc.domain.ReqStatCumulative as generatedAlias0 where ( generatedAlias1.processTimeSeconds>5L ) and ( generatedAlias1.processTimeSeconds<200L )
10:48:57.169 [main] DEBUG o.h.h.i.ast.QueryTranslatorImpl - --- HQL AST ---
 \-[QUERY] Node: 'query'
    +-[SELECT_FROM] Node: 'SELECT_FROM'
    |  +-[FROM] Node: 'from'
    |  |  \-[RANGE] Node: 'RANGE'
    |  |     +-[DOT] Node: '.'
    |  |     |  +-[DOT] Node: '.'
    |  |     |  |  +-[IDENT] Node: 'abc'
    |  |     |  |  \-[IDENT] Node: 'domain'
    |  |     |  \-[IDENT] Node: 'ReqStatCumulative'
    |  |     \-[ALIAS] Node: '**generatedAlias0**'
    |  \-[SELECT] Node: 'select'
    |     \-[COUNT] Node: 'count'
    |        \-[ROW_STAR] Node: '*'
    \-[WHERE] Node: 'where'
       \-[AND] Node: 'and'
          +-[GT] Node: '>'
          |  +-[DOT] Node: '.'
          |  |  +-[IDENT] Node: '**generatedAlias1**'
          |  |  \-[IDENT] Node: 'processTimeSeconds'
          |  \-[NUM_LONG] Node: '5L'
          \-[LT] Node: '<'
             +-[DOT] Node: '.'
             |  +-[IDENT] Node: '**generatedAlias1**'
             |  \-[IDENT] Node: 'processTimeSeconds'
             \-[NUM_LONG] Node: '200L'

10:48:57.169 [main] DEBUG o.h.hql.internal.ast.ErrorCounter - throwQueryException() : no errors
10:48:57.169 [main] DEBUG o.h.h.i.antlr.HqlSqlBaseWalker - select << begin [level=1, statement=select]
10:48:57.169 [main] DEBUG o.h.h.internal.ast.tree.FromElement - FromClause{level=1} : erf.domain.ReqStatCumulative (generatedAlias0) -> reqstatcum0_
10:48:57.169 [main] ERROR o.h.hql.internal.ast.ErrorCounter -  Invalid path: 'generatedAlias1.processTimeSeconds'
10:48:57.215 [main] ERROR o.h.hql.internal.ast.ErrorCounter -  Invalid path: 'generatedAlias1.processTimeSeconds'
org.hibernate.hql.internal.ast.InvalidPathException: Invalid path: 'generatedAlias1.processTimeSeconds'
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3 回答 3

19

您的代码失败，因为您Root对 count 和 where 子句使用不同的实例：第一个（按定义顺序）生成generatedAlias1别名，另一个生成generatedAlias0. 您需要重构代码以便Root在两个地方使用相同的实例：

CriteriaQuery<Long> cqCount = builder.createQuery(Long.class);
Root<ReqStatCumulative> entityRoot = cqCount.from(cqEntity.getResultType());
cqCount.select(builder.count(entityRoot));
Path<Long> processTimeSeconds = entityRoot.get("processTimeSeconds");
cqCount.where(qb.and(qb.greaterThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec()),//
                qb.lessThan(processTimeSeconds, (long) cfg.getProcessTimeExceedsSec() + 100))//
                );//    
return em.createQuery(cqCount).getSingleResult();
于 2013-01-16T17:44:43.903 回答
3

我有同样的问题，我解决了：

CriteriaQuery<Long> countCriteria = cb.createQuery(Long.class);
Root<EntityA> countRoot = countCriteria.from(cq.getResultType());
Set<Join<EntityA, ?>> joins = originalEntityRoot.getJoins();
for (Join<EntityA, ?> join :  joins) {
    countRoot.join(join.getAttribute().getName());
}
countCriteria.select(cb.count(countRoot));
if(finalPredicate != null)
    countCriteria.where(finalPredicate);

TypedQuery<Long> queryCount = entityManager.createQuery(countCriteria);
Long count = queryCount.getSingleResult();

在哪里

originalEntityRoot 是我使用 where 子句进行查询的主根。

于 2017-02-10T19:04:11.187 回答
3

我正在寻找基于 OP 问题的更通用的解决方案。并且只留下一个基于@Hector 示例的更通用的解决方案：

public class CountQueryHelper<T> {

    final Class<T> typeParameterClass;

    public CountQueryHelper(Class<T> typeParameterClass) {
        this.typeParameterClass = typeParameterClass;
    }

    public CriteriaQuery<Long> getCountQuery(CriteriaQuery<T> originalQuery, EntityManager em) {
        CriteriaBuilder cb = em.getCriteriaBuilder();

        // create count query
        CriteriaQuery<Long> countQuery = cb.createQuery(Long.class);


        // start copying root/joins/restrictions from  the original query

        // copy roots
        for (Root r : originalQuery.getRoots()) {
            Root root = countQuery.from(r.getModel());
            root.alias(r.getAlias());
        }

        // copy joins
        for (Root r : originalQuery.getRoots()) {
            Set<Join<T, ?>> joins = r.getJoins();
            for (Join<T, ?> join : joins) {
                for (Root countRoot : countQuery.getRoots()) {
                    try {
                        Join joinOnCount = countRoot.join(join.getAttribute().getName());
                        joinRecursive(joinOnCount, join);
                    } catch (IllegalArgumentException e) {
                        // attribute does not exist on this root
                    }
                }
            }
        }

        countQuery.select(cb.count(countQuery.from(this.typeParameterClass)));

        //  copy restrictions
        if (originalQuery.getRestriction() != null) {
            countQuery.where(originalQuery.getRestriction());
        }

        return countQuery;
    }

    private void joinRecursive(Join countJoins, Join<T, ?> originalJoin) {
        for(Join original : originalJoin.getJoins()) {
            Join<Object, Object> childJoin = countJoins.join(original.getAttribute().getName());
            joinRecursive(childJoin, original);
        }
    }
}
于 2018-09-17T22:37:15.710 回答