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这是我的代码
while x <= datetime.date.today(): print something
我怎样才能得到datetime.date.tomorrow()?
datetime.date.tomorrow()
使用datetime.timedelta():
datetime.timedelta()
tomorrow = datetime.date.today() + datetime.timedelta(days=1)
date()对 a和 a求和时timedelta(),仅使用.days属性。
date()
timedelta()
.days