php - mysql query match exact string or number

Question

I have result in MySQL table. I need to get result only where is only 6 not 26 in user_id not.

id   users_id

 15    6,5
 16    1,5
 18    2,8
 19    1,26
 20    6,26
 21    5,10
 22    28,6
 23    21,9 
 24    29,6

i am using MySQL query

SELECT * FROM WHERE users_id LIKE '%6%'

Result

id  user_id

15  6,5
19  1,26   why is this here..
20  6,26
22  28,6
24  29,6

result is not correct. i need only :

id  user_id

15  6,5
22  28,6
24  29,6

score 2 · Accepted Answer

Try::

SELECT  *
FROM    tableName
WHERE   user_id like '6,%' or user_id like '%,6' or user_id like '%,6,%'

score 1 · Accepted Answer

SELECT  *
FROM    tableName
WHERE   FIND_IN_SET(6, users_id) > 0 AND
        FIND_IN_SET(26, users_id) = 0

SOURCE

score 0 · Accepted Answer

because your query checks if the result contains a 6 at every place.

Obviously, 26 contains 6...

You could do (other ways exist)

where (users_id like '6,%' or users_id like '%,6')

score 0 · Accepted Answer

maybe try:

SELECT * FROM WHERE users_id IN ('6');

should just match the 6.

score 0 · Accepted Answer

Or without knowing about FIND_IN_SET or about 'OR' you just could:

id   users_id

 15    |6|5|
 16    |1|5|
 18    |2|6|

and select user_id like '%|6|%'

5 回答 5