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我想在表中插入一行时create new rows在 表中触发。ba

我有一张staff_leave_application这样的桌子:

id |  staff     |   leave type  | start date | end date       |  is half  |
---+------------+---------------+------------+----------------+-----------+
 1 | John Doe   |  Casual Leave | 17/01/2013 | 20/01/2013     |     0     |

如果在这个表中插入了一行,那么它将触发并插入到另一个表中leave

要插入到leave表中的数据:

拆分日期范围start date-end date到一天,例如:

17/01/2013 - 20/01/2013 will be

17/01/2013
18/01/2013
19/01/2013
20/01/2013

现在每天插入每行leave表,以及staff_leave_applications 列 ID, staff, leave type

感谢Sharsh,我按照@Shaharsh shah 的回答得到了这个。

DELIMITER $$

USE `mydb`$$

CREATE
    /*!50017 DEFINER = 'root'@'localhost' */
    TRIGGER `tn_air_staff_leave_application` AFTER INSERT ON `staff_leave_application` 
    FOR EACH ROW BEGIN
        SET @counter := -1; 
        WHILE (@counter < DATEDIFF(DATE(new.end_date), DATE(new.start_date))) DO 
            INSERT INTO `leave`(staff_id_staff, leave_type_id_leave_type, staff_leave_application_id_staff_leave_application, leave_date) 
            VALUES (new.staff_id_staff, new.leave_type_id_leave_type, new.id_staff_leave_application, DATE_ADD(new.start_date, INTERVAL @counter:=@counter + 1 DAY)); 
        END WHILE; 
END;
$$
4

1 回答 1

1

尝试这个:

DELIMITER $$

DROP TRIGGER /*!50032 IF EXISTS */ `tn_air_staff_leave_application`$$

CREATE
    /*!50017 DEFINER = 'root'@'localhost' */
    TRIGGER `tn_air_staff_leave_application` AFTER INSERT ON `staff_leave_application` 
    FOR EACH ROW BEGIN
        SET @counter := -1; 
        WHILE (@counter < DATEDIFF(DATE(new.endDate), DATE(new.startDate))) DO 
            INSERT INTO `leave`(staffId, leaveType, leaveDate) 
            VALUES (new.id, new.leaveType, DATE_ADD(new.startDate, INTERVAL @counter:=@counter + 1 DAY)); 
        END WHILE; 
END;
$$

DELIMITER ;

删除触发器

DELIMITER $$

DROP TRIGGER /*!50032 IF EXISTS */ `tn_adr_staff_leave_application`$$

CREATE
    /*!50017 DEFINER = 'root'@'localhost' */
    TRIGGER `tn_adr_staff_leave_application` AFTER DELETE ON `staff_leave_application` 
    FOR EACH ROW BEGIN
          DELETE FROM `leave` WHERE staffId = old.id;
END;
$$

DELIMITER ;
于 2013-01-16T09:38:53.617 回答