26

我WCF在 C# 中有一项服务。

在服务调用客户端发送一个城市名称。我想将城市名称转换为纬度和经度，并存储在人口统计下的数据库中。

我打算使用 Google API 来实现上述功能。

我从 Google 获得了一个 API 密钥及其“服务帐户”类型。

如何使用哪些 API 获取经纬度？

我需要安装一些SDK或任何REST服务吗？

4

5 回答 5

64

您可以尝试 NuGet 包GoogleMaps.LocationServices，或者只是旋转它的源代码。它使用 Google 的 REST API 来获取给定地址的纬度/经度，反之亦然，无需 API 密钥。

你像这样使用它：

public static void Main()
{
    var address = "Stavanger, Norway";

    var locationService = new GoogleLocationService();
    var point = locationService.GetLatLongFromAddress(address);

    var latitude = point.Latitude;
    var longitude = point.Longitude;

    // Save lat/long values to DB...
}
于 2013-01-16T09:35:46.217 回答
21

如果你想使用谷歌地图 API 看看他们的 REST API，你不需要安装谷歌地图 API 只需发送一个请求

http://maps.googleapis.com/maps/api/geocode/xml?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=true_or_false

你会得到一个响应 XML。

对于响应 JSON：

https://maps.googleapis.com/maps/api/geocode/json?address=1600+Estância+Sergipe,&key=**YOUR_API_KEY**

有关更多信息，请查看

https://developers.google.com/maps/documentation/geocoding/index#GeocodingRequests

于 2013-01-16T09:25:08.107 回答
7

您可以在特定的 url 中传递地址 .. 并在返回值 dt(datatable) 中获得纬度和经度

string url = "http://maps.google.com/maps/api/geocode/xml?address=" + address+ "&sensor=false";
WebRequest request = WebRequest.Create(url);

using (WebResponse response = (HttpWebResponse)request.GetResponse())
{
    using (StreamReader reader = new StreamReader(response.GetResponseStream(), Encoding.UTF8))
    {
        DataSet dsResult = new DataSet();
        dsResult.ReadXml(reader);
        DataTable dtCoordinates = new DataTable();
        dtCoordinates.Columns.AddRange(new DataColumn[4] { new DataColumn("Id", typeof(int)),
                    new DataColumn("Address", typeof(string)),
                    new DataColumn("Latitude",typeof(string)),
                    new DataColumn("Longitude",typeof(string)) });
        foreach (DataRow row in dsResult.Tables["result"].Rows)
        {
            string geometry_id = dsResult.Tables["geometry"].Select("result_id = " + row["result_id"].ToString())[0]["geometry_id"].ToString();
            DataRow location = dsResult.Tables["location"].Select("geometry_id = " + geometry_id)[0];
            dtCoordinates.Rows.Add(row["result_id"], row["formatted_address"], location["lat"], location["lng"]);
        }
    }
    return dtCoordinates;
}
于 2016-03-17T07:41:19.857 回答
6 
     /*Ready to use code :  simple copy paste GetLatLong*/
    public class AddressComponent
    {
        public string long_name { get; set; }
        public string short_name { get; set; }
        public List<string> types { get; set; }
    }

    public class Northeast
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Southwest
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Bounds
    {
        public Northeast northeast { get; set; }
        public Southwest southwest { get; set; }
    }

    public class Location
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Northeast2
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Southwest2
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Viewport
    {
        public Northeast2 northeast { get; set; }
        public Southwest2 southwest { get; set; }
    }

    public class Geometry
    {
        public Bounds bounds { get; set; }
        public Location location { get; set; }
        public string location_type { get; set; }
        public Viewport viewport { get; set; }
    }

    public class Result
    {
        public List<AddressComponent> address_components { get; set; }
        public string formatted_address { get; set; }
        public Geometry geometry { get; set; }
        public string place_id { get; set; }
        public List<string> types { get; set; }
    }

    public class RootObject
    {
        public List<Result> results { get; set; }
        public string status { get; set; }
    }


    public static RootObject GetLatLongByAddress(string address)
    {
        var root = new RootObject();

        var url =
            string.Format(
                "http://maps.googleapis.com/maps/api/geocode/json?address={0}&sensor=true_or_false", address);
        var req = (HttpWebRequest)WebRequest.Create(url);

        var res = (HttpWebResponse)req.GetResponse();

        using (var streamreader=new StreamReader(res.GetResponseStream()))
        {
            var result = streamreader.ReadToEnd();

            if (!string.IsNullOrWhiteSpace(result))
            {
                root = JsonConvert.DeserializeObject<RootObject>(result);
            }
        }
        return root;


    }


          /* Call This*/

var destination_latLong = GetLatLongByAddress(um.RouteDestination);

var lattitude =Convert.ToString( destination_latLong.results[0].geometry.location.lat, CultureInfo.InvariantCulture);

 var longitude=Convert.ToString( destination_latLong.results[0].geometry.location.lng, CultureInfo.InvariantCulture);
于 2016-05-24T07:37:18.870 回答
0

Google 的替代方案是OpenStreetMap 的 Nominatim API。

与 Google 不同，只要您不过度使用它们（每秒超过 1 个请求），它们就没有每日限制。下面的代码适用于 Blazor 服务器。

    [Inject] IJSRuntime _js { get; set; }

    public async Task<Coordinates> GetCoordinates(string city) {
        Coordinates coordinates = new Coordinates();
        string query= String.Format("https://nominatim.openstreetmap.org/search.php?q={0}&format=jsonv2", city);
        string result = GetRequest(query); //returns a stringified array of js objects
        IJSObjectReference objArray= await _js.InvokeAsync<IJSObjectReference>("JSON.parse", result); //parse the string to a js array
        IJSObjectReference obj = await objArray.InvokeAsync<IJSObjectReference>("shift"); //take the first element in the array
        string jsonResult = await _js.InvokeAsync<string>("JSON.stringify", obj);
        dynamic dynamicResult = JObject.Parse(jsonResult);
        coordinates.Latitude= dynamicResult.lat;
        coordinates.Longitude= dynamicResult.lon;
        return coordinates;

    }

    public string GetRequest(string url) {
        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
        request.AutomaticDecompression = DecompressionMethods.GZip | DecompressionMethods.Deflate;
        request.UserAgent = @"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/51.0.2704.106 Safari/537.36";
        using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
        using (Stream stream = response.GetResponseStream())
        using (StreamReader reader = new StreamReader(stream))
        {
            return reader.ReadToEnd();
        }
    }

    public class Coordinates {
        public double Longitude { get; set; }
        public double Latitude { get; set; }
    }
于 2021-11-15T21:05:57.997 回答