是否可以在没有类的情况下使用命名空间?
例如:
namespace Foo;
// rest of the procedural code and functions
问是因为我知道命名空间只在有类的地方使用。
谢谢你的帮助。
是否可以在没有类的情况下使用命名空间?
例如:
namespace Foo;
// rest of the procedural code and functions
问是因为我知道命名空间只在有类的地方使用。
谢谢你的帮助。
是的,您可以使用没有类的命名空间,例如:
//demo.php file
namespace FooDemo;
function first() { return "First"; }
function second() { return "Second"; }
function third() { return "Third"; }
//test.php file
require_once 'demo.php';
foreach (array("first","second","third") as $funcs) {
echo call_user_func('FooDemo\\'.$funcs);
}
你的意思是这样的吗
是的。见documentation
。
提炼:
<?php
namespace Foo\Bar;
include 'file1.php';
const FOO = 2;
function foo() {}
class foo
{
static function staticmethod() {}
}
/* Unqualified name */
foo(); // resolves to function Foo\Bar\foo
foo::staticmethod(); // resolves to class Foo\Bar\foo, method staticmethod
echo FOO; // resolves to constant Foo\Bar\FOO
/* Qualified name */
subnamespace\foo(); // resolves to function Foo\Bar\subnamespace\foo
subnamespace\foo::staticmethod(); // resolves to class Foo\Bar\subnamespace\foo,
// method staticmethod
echo subnamespace\FOO; // resolves to constant Foo\Bar\subnamespace\FOO
/* Fully qualified name */
\Foo\Bar\foo(); // resolves to function Foo\Bar\foo
\Foo\Bar\foo::staticmethod(); // resolves to class Foo\Bar\foo, method staticmethod
echo \Foo\Bar\FOO; // resolves to constant Foo\Bar\FOO
?>