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我已经实现了一个 spring mvc 3 代码来获取 JSON 响应（在 jackson mapper 的帮助下）

@RequestMapping(value = "/getallroles", method = RequestMethod.GET)
@ResponseBody
public JsonJtableResponse1 getAllRoles(){
    List<Role> roleList = testService.getAllRoles();
    JsonJtableResponse1 jstr = new JsonJtableResponse1("OK",roleList);
    return jstr;
}

JSON 响应对象是这样的。

public class JsonJtableResponse1 {

    private String Result;

    private List<Role> Records;

    public JsonJtableResponse1(String Result) {
        this.Result = Result;
    }

    public JsonJtableResponse1(List<Role> Records) {
        this.Records = Records;
    }

    public JsonJtableResponse1(String Result, List<Role> Records) {
        this.Result = Result;
        this.Records = Records;
    }

    public String getResult() {
        return Result;
    }

    public void setResult(String Result) {
        this.Result = Result;
    }

    public List<Role> getRecords() {
        return Records;
    }

    public void setRecords(List<Role> Records) {
        this.Records = Records;
    }   
}

从 spring 方法 getAllRoles() 返回的 JSON 是

{"result":"OK","records":[
{"custId":"1","name":"aaa","birthYear":"1982","employer":"XX","infoAsOfDate":"20130110","disabled":"true"},
{"custId":"2","name":"bbb","birthYear":"1982","employer":"YY","infoAsOfDate":"20130111","disabled":"true"},
{"custId":"3","name":"ccc","birthYear":"1982","employer":"XX","infoAsOfDate":"20130108","disabled":"false"},
{"custId":"4","name":"ddd","birthYear":"1981","employer":"TT","infoAsOfDate":"20130107","disabled":"true"}
]}

我需要 JSON 作为 - [注意两个元素中的大写 R]

{"Result":"OK","Records":[ ....................
 ..............................................
]}

使用 Jakson 映射器创建 JSON 响应时考虑了对象的 getter/setter 名称。如何实现所需的 JSON 响应格式？

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1 回答 1

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您可以使用注释自定义名称@JsonProperty：

@JsonProperty("Result")
public String getResult() {
    return Result;
}

如果您需要将所有属性名称的第一个字母大写，则可以通过扩展PropertyNamingStrategy. 例如，您可以阅读这篇博文http://www.cowtowncoder.com/blog/archives/2011/03/entry_448.html。

于 2013-01-16T00:48:13.540 回答