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我刚开始研究一个非常基本的计算器程序,它运行良好,我无法让它在完成计算后保持程序打开。io.read() 似乎不起作用。我的代码如下:

promptmethod = "Would you like to use addition, subtraction, multiplication, or           division?"
promptnumber1 = "Enter a number:"
promptnumber2 = "Enter another number:"
anotherprompt = "Would you like to make another calculation?"

print(promptmethod)
usermethod = io.read("*line")
print(promptnumber1)
number1 = io.read("*number")
print(promptnumber2)
number2 = io.read("*number")

if usermethod == "addition" then
answer = number1 + number2
stringanswer = "Your calculation is " .. number1 .. " + " .. number2 .. " = " .. answer
elseif usermethod == "subtraction" then
answer = number1 - number2
stringanswer = "Your calculation is " .. number1 .. " - " .. number2 .. " = " .. answer
elseif usermethod == "multiplication" then
answer = number1 * number2
stringanswer = "Your calculation is " .. number1 .. " × " .. number2 .. " = " .. answer
elseif usermethod == "division" then
answer = number1 / number2
stringanswer = "Your calculation is " .. number1 .. " ÷ " .. number2 .. " = " .. answer
else
error("Invalid operation or values.")
end

print(stringanswer)

io.read()

有谁知道为什么会发生这种情况?谢谢!

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1 回答 1

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一个更简单的例子:

io.read('*number')
io.read()

问题是read('*number')不消耗数字后的换行符。由于它仍然位于输入流上,因此当您调用io.read(默认为读取一行)时,它会立即返回。

要解决这个问题,只需再打io.read一次。

于 2013-01-15T18:20:16.550 回答