1

我反复得到

Error: Unexpected. Please try again.

使用此查询:

SELECT Pollen.start, DNase.start, DNase.DNasecleavage
FROM   DNAse_raw_seq.DNAse_raw_seq_Chr1_table AS DNase
JOIN   DNAse_raw_seq.polleninput AS Pollen
       ON DNase.start  = Pollen.start
       where Pollen.GeneID contains "At1";

昨天我在类似的 table2 上使用了相同的查询,效果很好。感谢您的任何建议!

4

2 回答 2

2

知道了!

功能查询如下所示

SELECT Pollen.GeneID, Pollen.start, DNase.DNasecleavage
FROM   DNAse_raw_seq.DNAse_raw_seq_Chr1_table AS DNase
JOIN   DNAse_raw_seq.polleninput AS Pollen
       ON DNase.start = Pollen.start
       where Pollen.GeneID contains "At1";

我不允许选择 DNase.start....

于 2013-01-15T12:08:46.990 回答
0
SELECT Pollen.start, DNase.start, DNase.DNasecleavage
FROM   DNAse_raw_seq.DNAse_raw_seq_Chr1_table AS DNase
JOIN   DNAse_raw_seq.polleninput AS Pollen
       ON DNase.start  = Pollen.start
       where Pollen.GeneID contains "At1";

您想在“Pollen.GeneID”上使用 where 但您没有选择它。您可以通过将其添加到选择来修复它。像这样:

SELECT Pollen.GeneID, Pollen.start, DNase.start, DNase.DNasecleavage
FROM   DNAse_raw_seq.DNAse_raw_seq_Chr1_table AS DNase
JOIN   DNAse_raw_seq.polleninput AS Pollen
       ON DNase.start  = Pollen.start
       where Pollen.GeneID contains "At1";
于 2013-01-21T16:56:27.910 回答