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这是一种基于特定列值随机打乱某些数据库表条目的简单方法。感谢cbrulak的帮助,它现在可以正常运行。它无论如何都不是最有效的,但我想我会在修复后发布它,因为有人可能会觉得它有点用。

/* The method will shuffle the specific entries in the table, based on column value */
public void shuffleDeck(int deck_id){

    int i, j, count;
    int loop1, loop2;
    int num;
    int id1, id2;
    Random rand = new Random();
    String front1, back1, front2, back2;


    /* Create two separate content values for swapping the values between the two rows */
    ContentValues updated_1 = new ContentValues();
    ContentValues updated_2 = new ContentValues();

    String[] columns = new String[]{CARD_ROWID, CARD_FRONT, CARD_BACK};

    /* Create two cursors pointing to the same query */
    Cursor cursor1 = Database.query(CARDS_TABLE, columns, DECK_ROWID + " = " + deck_id, 
            null, null, null, null);
    Cursor cursor2 = Database.query(CARDS_TABLE, columns, DECK_ROWID + " = " + deck_id, 
            null, null, null, null);

    cursor1.moveToFirst();
    cursor2.moveToFirst();

    int iRow = cursor1.getColumnIndex(CARD_ROWID);
    int iFront = cursor1.getColumnIndex(CARD_FRONT);
    int iBack = cursor1.getColumnIndex(CARD_BACK);

    /* Get total number of entries in the cursor */
    count = cursor1.getCount();

    /* Loop through  */
    for(i=1; i<=count; i++){
        num = rand.nextInt(count) + 1;

        /* Acquire the values from the current row that will be inserted into the randomly selected row */
        id1 = cursor1.getInt(iRow);
        front1 = cursor1.getString(iFront);
        back1 = cursor1.getString(iBack);

        /* Move to the next row in cursor2 for a random number of times */
        for (j=1; j<num; j++){

            cursor2.moveToNext();
            /* Fail safe to make sure it doesn't go out of bounds */
            if(cursor2.isLast())
                break;
        }

        /* Acquire the values from the random row */
        front2 = cursor2.getString(iFront);
        back2 = cursor2.getString(iBack);
        id2 = cursor2.getInt(iRow);

        /* Check to see if the second cursor is also pointing to the same position. */
        if(!(front1.equals(front2) && back1.equals(back2))){
            updated_1.put(CARD_FRONT, front2);
            updated_1.put(CARD_BACK, back2);
            updated_2.put(CARD_FRONT, front1);
            updated_2.put(CARD_BACK, back1);

            /* Call the database to UPDATE the values */
            Database.update(CARDS_TABLE, updated_1, CARD_ROWID + " = " + id1, null);
            Database.update(CARDS_TABLE, updated_2, CARD_ROWID + " = " + id2, null);

            /* Clear the content values */
            updated_1.remove(CARD_FRONT);
            updated_1.remove(CARD_BACK);
            updated_2.remove(CARD_FRONT);
            updated_2.remove(CARD_BACK);

            /* Requery the cursors */
            cursor1 = Database.query(CARDS_TABLE, columns, DECK_ROWID + " = " + deck_id, 
                    null, null, null, null);
            cursor2 = Database.query(CARDS_TABLE, columns, DECK_ROWID + " = " + deck_id, 
                    null, null, null, null);

            /* Move cursor1 to the same position it was, right before requerying it */
            for(loop1 = 1; loop1<=i; loop1++){
                cursor1.moveToNext();

                /* Fail save in case it tries to go out of bound */
                if(cursor1.isLast()) 
                    break;
            }
            /* Move cursor2 to the same position it was, right before requerying it */
            for(loop2 = 1; loop2<=j; loop2++){
                cursor2.moveToNext();

                /* Fail save in case it tries to go out of bound */
                if(cursor2.isLast()) 
                    break;
            }
        }
        /* Move the cursors to the new positions */
        cursor1.moveToNext();
        cursor2.moveToFirst();
    }
    cursor1.close();
    cursor2.close();
}
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1 回答 1

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更新后请求一个新的游标。

请参阅:Android - 您可以为 SQLite 结果更新光标吗?

更重要的是:http: //developer.android.com/reference/android/database/Cursor.html#requery()(他们说要请求新的)

给您的奖励积分:使用内容提供商。为您节省大量头痛。

于 2013-01-15T20:56:25.743 回答