python - 将字符串转换为 datime.time，错误？

Question

我正在以字符串格式获取时间数据，例如“HH:MM”，例如“13:33”将是 13 小时 33 分钟。

所以，我用这段代码来获取时间对象，效果很好

datetime.datetime.strptime('13:33', '%H:%M').time()

但是，我现在有新问题。新的字符串开始出现超过 24 小时，并且datetime.datetime.strptime('25:33', '%H:%M').time()会失败。你的建议是什么？

Answer 1

A datetime.time object represents a (local) time of day, independent of any particular day.

You shouldn't use it to represent an elapsed time, like you appear to be.

More appropriate might be a datetime.timedelta:

A timedelta object represents a duration, the difference between two dates or times.

class datetime.timedelta([days[, seconds[, microseconds[, milliseconds[, minutes[, hours[, weeks]]]]]]])

All arguments are optional and default to 0. Arguments may be ints, longs, or floats, and may be positive or negative.

An example:

>>> from datetime import timedelta
>>> d = timedelta(hours=25,minutes=10)
>>> d
datetime.timedelta(1, 4200) #Days, seconds

Answer 2

唉，您必须手动执行此操作。

def parse_stopwatch(s):
    hours, minutes = s.split(':', 1)
    return datetime.time(hour=int(hours), minute=int(minutes))

这真是愚蠢，理所当然。您可以自动将超过 60 分钟的时间转换为小时，或者使用正则表达式获得所有幻想，或者添加几天或几秒钟的支持。但是您必须更具体地了解这些数据的来源以及它应该代表什么。:)

Answer 3

当你说“它只会失败”时，我假设你想知道它什么时候会失败。这是一种方法：

>>> import datetime
>>>
>>> time_strs = [
... "13:33",
... "25:33",
... "12:88"
... ]
>>>
>>> for s in time_strs:
...     try:
...         print datetime.datetime.strptime(s, '%H:%M').time()
...     except ValueError:
...         print "Bad time: {0}".format(s)
...
13:33:00
Bad time: 25:33
Bad time: 12:88