6

表型号:

public class UserOwnerShip
{
    public virtual int Id { get; set; }
    public virtual User User { get; set; }
    public virtual City City { get; set; }
    public virtual Company Company { get; set; }
    public virtual UserRole UserRole { get; set; }
    public virtual DateTime RegistryDate { get; set; }
    public virtual bool IsActive { get; set; }
}

映射:

internal class UserOwnerShipMap : ClassMap<UserOwnerShip>
{
    public UserOwnerShipMap()
    {
        Id(x => x.Id);
        Map(x => x.IsActive);
        Map(x => x.UserRole).CustomType(typeof(int));
        Map(x => x.RegistryDate);

        References(x => x.User).Not.Nullable();
        References(x => x.City).Nullable();
        References(x => x.Company).Nullable();
    }
}

我的 EnumConvention 类:

public class EnumConvention : IUserTypeConvention
{
    public void Accept(IAcceptanceCriteria<IPropertyInspector> criteria)
    {
        criteria.Expect(x => x.Property.PropertyType.IsEnum ||
            (x.Property.PropertyType.IsGenericType &&
             x.Property.PropertyType.GetGenericTypeDefinition() == typeof(Nullable<>) &&
             x.Property.PropertyType.GetGenericArguments()[0].IsEnum)
            );
    }

    public void Apply(IPropertyInstance target)
    {
        target.CustomType(target.Property.PropertyType);
    }
}

和 UserRole 枚举

public enum UserRole
{
    User,
    Operator,
    Manager,
    Manager,
    Admin
}

还有我的休眠配置部分:

....().Conventions.AddFromAssemblyOf<EnumConvention>())

所以当我查询时:

    IList<UserOwnerShip> userOwnerShip = session.QueryOver<UserOwnerShip>()
                                                    .Where(u => u.UserRole == UserRole.Owner)
                                                    .Where(u => u.IsActive)
                                                    .List<UserOwnerShip>();

我有例外:

Type mismatch in NHibernate.Criterion.SimpleExpression: UserRole expected type System.Int32, actual type XXX.XXX.UserRole (which is enum type class)
4

1 回答 1

8

如果要存储枚举的 int 值,映射很简单:

Map(x => x.UserRole).CustomType<UserRole>();

不需要 EnumConvention。

于 2013-01-15T01:04:22.567 回答