正如克里斯辛克莱在上面的评论中指出的那样;您可以使用委托而不使用反射或表达式树来获取MethodInfo
. 缺点是编译器无法推断出泛型参数,因此您必须指定委托类型以匹配给定方法的签名,如下所示:
public class Test
{
public static void Main()
{
var t = new Test();
CheckMethodAttributes<Action>(t.Test1);
CheckMethodAttributes<Action<int>>(t.Test2);
CheckMethodAttributes<Action<object, string, bool>>(t.Test3);
}
public void Test1() { }
public void Test2(int a) { }
public void Test3(object a, string c, bool d) { }
public static void CheckMethodAttributes<T>(T func)
{
MethodInfo method = new MethodOf<T>(func);
// Example attribute check:
var ignoreAttribute = method.GetAttribute<IgnoreAttribute>();
if (ignoreAttribute != null)
{
// Do something here...
}
}
}
这使用了两个实用程序类,用于从给定MethodOf<T>
中提取和一些用于获取强类型自定义属性检索:MethodInfo
Delegate
AttributeUtils
public static class AttributeUtils
{
public static bool HasAttribute<TAttribute>(this MemberInfo member, bool inherit = true)
where TAttribute : Attribute
{
return member.IsDefined(typeof(TAttribute), inherit);
}
public static TAttribute GetAttribute<TAttribute>(this MemberInfo member, bool inherit = true)
where TAttribute : Attribute
{
return member.GetAttributes<TAttribute>(inherit).FirstOrDefault();
}
public static IEnumerable<TAttribute> GetAttributes<TAttribute>(this MemberInfo member, bool inherit = true)
where TAttribute : Attribute
{
return member.GetCustomAttributes(typeof(TAttribute), inherit).Cast<TAttribute>();
}
}
public class MethodOf<T>
{
public MethodOf(T func)
{
var del = func as Delegate;
if (del == null) throw new ArgumentException("Cannot convert func to Delegate.", "func");
Method = del.Method;
}
private MethodInfo Method { get; set; }
public static implicit operator MethodOf<T>(T func)
{
return new MethodOf<T>(func);
}
public static implicit operator MethodInfo(MethodOf<T> methodOf)
{
return methodOf.Method;
}
}