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如何访问子类属性?,我可以访问 Y 属性,在这种情况下是名称,但不是 x,另一种情况是相同的,但不是 x 的单个引用,而是带有 x 的列表,在第二种情况下,如何迭代每个对象.

    public class X
{
    public int ID{get;set;} 
    public int Name{get;set;}
}

public class y
{

    public string Name{get;set;}
    public x Reference{get:set;}
}

    //second case 
public class y
{

    public string Name{get;set;}
    public List<x> Reference{get:set;}
}



public static void Main()
{
    y classY = new y();
    y.Name = "some text here";
    y.x.ID = "1";
    y.x.Name ="some text for x here";
}

// in another class, pass y
// so, in this method I only can get 'y' values, but not x
Hashtable table = new Hashtable();
public void GetProperties(object p)
{
    Type mytype = p.GetType();
    var properties = mytype.GetProperties(BindingFlags.Public | BindingFlags.Instance);

    foreach (var property in properties)
    {
        table.Add(property.Name, property.GetValue(p, null));
    }   
}

更新

也试试界面

public interface ISub
{}
public class X : ISub // etc....


if (typeof(ISub).IsAssignableFrom(property.GetType()) ) // this alwas as false 
4

1 回答 1

0

您必须评估每个属性以了解它是否是列表:

foreach (var prop in properties)
{
    var obj = prop.GetValue(p, null);
    if (obj is List<x>)
    {
        var list = obj as List<x>;
        // do something with your list
    }
    else
    {
        table.Add(prop.Name, obj);
    }
}   
于 2013-01-14T17:17:55.420 回答