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我正在尝试使用 AJAX 从 PHP 中检索两个数组,但我认为json_encode只能有一个变量。你知道我该如何解决这个问题吗?我是新手,正在使用json_encode

<?php
while($row = mysql_fetch_array($get_grades_boy)){

                $data_grades_boys[]=array(
                    'fname_b'=>$row['firstname'],
                    'mname_b' => $row['middlename'],
                    'lname_b' => $row['lastname'],
                    'studnt_id_b' => $row['student_id'],
                    'grade_b' => $row['grade'],
                    ); 
             }

             while($row2 = mysql_fetch_assoc($get_grades_girl)){

                $data_grades_girls[]=array(
                    'fname_g'=>$row2['firstname'],
                    'mname_g' => $row2['middlename'],
                    'lname_g' => $row2['lastname'],
                    'studnt_id_g' => $row2['student_id'],
                    'grade_g' => $row2['grade'],
                    ); 
             }
echo json_encode($data_grades_boys);

我试着这样做

  echo json_encode($data_grades_boys);
echo json_encode($data_grades_girls);

检索,但它没有工作。

4

1 回答 1

1

您需要将两个数组组合成一个数组:

$data_grades = array(
    'boys'  => $data_grades_boys,
    'girls' => $data_grades_girls
);
echo json_encode($data_grades);

和jQuery:

$ajax(
...
success: function(data) {
    boys = data.boys;
    girls = data.girls

然后

$.each(boys).function(index, value) {
于 2013-01-13T17:33:15.557 回答