javascript - Javascript 对象构造函数和布尔变量

Question

我正在尝试创建一个 JS 对象构造函数，但想使用布尔运算声明对象的属性之一。不知何故我弄错了 - 请指教！

谢谢！交流电

function Student(gender, name, id, age, likes) {
this.gender = gender;
this.name = name;
this.id = id;
this.age = Boolean () {
    var age = x;
    if (age >= 21) {
    return "adult";
    } else {
    return "minor";
  }     
  };
this.likes = likes;
 }

window.onload = init;

function init() {
var jessica = new Student("female", "Jessica", 12, 21, ["butterflies", "flowers", "music"]);
var jessicaJSON = JSON.stringify(jessica);
console.log(jessicaJSON);

var anotherJessica = JSON.parse(jessicaJSON);
console.log(anotherJessica);

}

Answer 1

这是为您修复的学生功能。使用三元 if 语句而不是真正无效的 "Boolean() {}"无论如何都是布尔类型。

function Student(gender, name, id, age, likes) {
  this.gender = gender;
  this.name = name;
  this.id = id;
  this.likes = likes;
  this.age = (age >= 21 ? "adult" : "minor");
} 

Answer 2

我想这就是你需要的：

function Student(gender, name, id, age, likes) {
  this.gender = gender;
  this.name = name;
  this.id = id;
  this.age = (age >= 21) ? "adult" : "minor";
  this.likes = likes;
}

var jessica = new Student("female", "Jessica", 12, 21, ["butterflies", "flowers", "music"]);
console.log(jessica.age); //adult

这里我使用三元条件运算符：condition ? value_if_true : value_if_false.

在这种情况下，条件是age >= 21，如果为真"adult"，则值为，如果为假，则值为"minor"。

Answer 3

function Student(gender, name, id, age, likes) {
    this.gender = gender;
    this.name = name;
    this.id = id;
    this.age = (age >= 21) ? "adult":"minor";
    this.likes = likes;
}

示例：http: //jsfiddle.net/av5ym/1/

Answer 4

其他人告诉你你应该做什么，但这里有一个本着你的代码精神的答案，以防你需要的不仅仅是一个布尔三元。

this.age = (function () {
    if (age >= 21) {
        return "adult";
    } else {
        return "minor";
    }     
}();