有没有办法用底图（或没有底图，如果有其他方法）绘制大陆边界，而不会出现那些烦人的河流？尤其是那条连大海都没有的金刚河，令人不安。
编辑：我打算在地图上进一步绘制数据，就像在底图库中一样（并且仍然将大陆的边界线绘制为数据上的黑线，为世界地图提供结构）所以虽然下面 Hooked 的解决方案很好，甚至高手，也不适用于此目的。
图片制作者：
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
m = Basemap(projection='robin',lon_0=0,resolution='c')
m.fillcontinents(color='gray',lake_color='white')
m.drawcoastlines()
plt.savefig('world.png',dpi=75)
出于这样的原因，我经常一起避免使用 Basemap 并使用 OGR 读取 shapefile 并将它们自己转换为 Matplotlib 艺术家。这是更多的工作，但也提供了更多的灵活性。
底图具有一些非常简洁的功能，例如将输入数据的坐标转换为您的“工作投影”。
如果您想坚持使用底图，请获取一个不包含河流的 shapefile。例如，自然地球在物理部分有一个很好的“土地”形状文件（下载“比例等级”数据并解压缩）。见http://www.naturalearthdata.com/downloads/10m-physical-vectors/
您可以使用 Basemap 中的 m.readshapefile() 方法读取 shapefile。这允许您在投影坐标中获取 Matplotlib 路径顶点和代码，然后您可以将其转换为新路径。它有点绕道，但它为您提供了来自 Matplotlib 的所有样式选项，其中大部分不能通过 Basemap 直接获得。它有点骇人听闻，但我现在在坚持底图时没有另一种方式。
所以：
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
from matplotlib.collections import PathCollection
from matplotlib.path import Path
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
# MPL searches for ne_10m_land.shp in the directory 'D:\\ne_10m_land'
m = Basemap(projection='robin',lon_0=0,resolution='c')
shp_info = m.readshapefile('D:\\ne_10m_land', 'scalerank', drawbounds=True)
ax = plt.gca()
ax.cla()
paths = []
for line in shp_info[4]._paths:
paths.append(Path(line.vertices, codes=line.codes))
coll = PathCollection(paths, linewidths=0, facecolors='grey', zorder=2)
m = Basemap(projection='robin',lon_0=0,resolution='c')
# drawing something seems necessary to 'initiate' the map properly
m.drawcoastlines(color='white', zorder=0)
ax = plt.gca()
ax.add_collection(coll)
plt.savefig('world.png',dpi=75)
给出：
如果您想对图像进行后处理（而不是直接使用底图），您可以移除未连接到海洋的水体：
import pylab as plt
A = plt.imread("world.png")
import numpy as np
import scipy.ndimage as nd
import collections
# Get a counter of the greyscale colors
a = A[:,:,0]
colors = collections.Counter(a.ravel())
outside_and_water_color, land_color = colors.most_common(2)
# Find the contigous landmass
land_idx = a == land_color[0]
# Index these land masses
L = np.zeros(a.shape,dtype=int)
L[land_idx] = 1
L,mass_count = nd.measurements.label(L)
# Loop over the land masses and fill the "holes"
# (rivers without outlays)
L2 = np.zeros(a.shape,dtype=int)
L2[land_idx] = 1
L2 = nd.morphology.binary_fill_holes(L2)
# Remap onto original image
new_land = L2==1
A2 = A.copy()
c = [land_color[0],]*3 + [1,]
A2[new_land] = land_color[0]
# Plot results
plt.subplot(221)
plt.imshow(A)
plt.axis('off')
plt.subplot(222)
plt.axis('off')
B = A.copy()
B[land_idx] = [1,0,0,1]
plt.imshow(B)
plt.subplot(223)
L = L.astype(float)
L[L==0] = None
plt.axis('off')
plt.imshow(L)
plt.subplot(224)
plt.axis('off')
plt.imshow(A2)
plt.tight_layout() # Only with newer matplotlib
plt.show()
第一张图像是原始图像，第二张是地块。第三个不是必需的，但很有趣，因为它标识了每个单独的连续陆地。第四张图片就是你想要的，去掉了“河流”的图像。
按照 user1868739 的示例，我只能选择我想要的路径（对于某些湖泊）：
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
m = Basemap(resolution='c',projection='robin',lon_0=0)
m.fillcontinents(color='white',lake_color='white',zorder=2)
coasts = m.drawcoastlines(zorder=1,color='white',linewidth=0)
coasts_paths = coasts.get_paths()
ipolygons = range(83) + [84] # want Baikal, but not Tanganyika
# 80 = Superior+Michigan+Huron, 81 = Victoria, 82 = Aral, 83 = Tanganyika,
# 84 = Baikal, 85 = Great Bear, 86 = Great Slave, 87 = Nyasa, 88 = Erie
# 89 = Winnipeg, 90 = Ontario
for ipoly in ipolygons:
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][2] for i in xrange(len(polygon_vertices))]
m.plot(px,py,linewidth=0.5,zorder=3,color='black')
plt.savefig('world2.png',dpi=100)
但这仅在为大陆使用白色背景时才有效。如果我在下面的行中更改color为'gray'，我们会看到其他河流和湖泊没有填充与大陆相同的颜色。（同样玩弄area_thresh不会删除那些与海洋相连的河流。）
m.fillcontinents(color='gray',lake_color='white',zorder=2)
白色背景的版本足以对大陆上的各种土地信息进行进一步的彩色绘图，但如果想要保留大陆的灰色背景，则需要更精细的解决方案。
我经常修改 Basemap 的 drawcoastlines() 以避免那些“破碎”的河流。为了数据源的一致性，我还修改了 drawcountries()。
这是我用来支持自然地球数据中可用的不同分辨率的内容：
from mpl_toolkits.basemap import Basemap
class Basemap(Basemap):
""" Modify Basemap to use Natural Earth data instead of GSHHG data """
def drawcoastlines(self):
shapefile = 'data/naturalearth/coastline/ne_%sm_coastline' % \
{'l':110, 'm':50, 'h':10}[self.resolution]
self.readshapefile(shapefile, 'coastline', linewidth=1.)
def drawcountries(self):
shapefile = 'data/naturalearth/countries/ne_%sm_admin_0_countries' % \
{'l':110, 'm':50, 'h':10}[self.resolution]
self.readshapefile(shapefile, 'countries', linewidth=0.5)
m = Basemap(llcrnrlon=-90, llcrnrlat=-40, urcrnrlon=-30, urcrnrlat=+20,
resolution='l') # resolution = (l)ow | (m)edium | (h)igh
m.drawcoastlines()
m.drawcountries()
这是输出：
请注意，默认情况下，底图使用 resolution='c'（粗略），显示的代码不支持此功能。
如果您可以绘制轮廓而不是 shapefile，那么绘制可以从任何地方获得的海岸线非常容易。我从 NOAA 海岸线提取器以 MATLAB 格式获取了我的海岸线： http ://www.ngdc.noaa.gov/mgg/shorelines/shorelines.html
为了编辑海岸线，我将其转换为 SVG，然后使用 Inkscape 对其进行编辑，然后再转换回 lat/lon 文本文件（“MATLAB”格式）。
所有 Python 代码都包含在下面。
# ---------------------------------------------------------------
def plot_lines(mymap, lons, lats, **kwargs) :
"""Plots a custom coastline. This plots simple lines, not
ArcInfo-style SHAPE files.
Args:
lons: Longitude coordinates for line segments (degrees E)
lats: Latitude coordinates for line segments (degrees N)
Type Info:
len(lons) == len(lats)
A NaN in lons and lats signifies a new line segment.
See:
giss.noaa.drawcoastline_file()
"""
# Project onto the map
x, y = mymap(lons, lats)
# BUG workaround: Basemap projects our NaN's to 1e30.
x[x==1e30] = np.nan
y[y==1e30] = np.nan
# Plot projected line segments.
mymap.plot(x, y, **kwargs)
# Read "Matlab" format files from NOAA Coastline Extractor.
# See: http://www.ngdc.noaa.gov/mgg/coast/
lineRE=re.compile('(.*?)\s+(.*)')
def read_coastline(fname, take_every=1) :
nlines = 0
xdata = array.array('d')
ydata = array.array('d')
for line in file(fname) :
# if (nlines % 10000 == 0) :
# print 'nlines = %d' % (nlines,)
if (nlines % take_every == 0 or line[0:3] == 'nan') :
match = lineRE.match(line)
lon = float(match.group(1))
lat = float(match.group(2))
xdata.append(lon)
ydata.append(lat)
nlines = nlines + 1
return (np.array(xdata),np.array(ydata))
def drawcoastline_file(mymap, fname, **kwargs) :
"""Reads and plots a coastline file.
See:
giss.basemap.drawcoastline()
giss.basemap.read_coastline()
"""
lons, lats = read_coastline(fname, take_every=1)
return drawcoastline(mymap, lons, lats, **kwargs)
# =========================================================
# coastline2svg.py
#
import giss.io.noaa
import os
import numpy as np
import sys
svg_header = """<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!-- Created with Inkscape (http://www.inkscape.org/) -->
<svg
xmlns:dc="http://purl.org/dc/elements/1.1/"
xmlns:cc="http://creativecommons.org/ns#"
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:svg="http://www.w3.org/2000/svg"
xmlns="http://www.w3.org/2000/svg"
version="1.1"
width="360"
height="180"
id="svg2">
<defs
id="defs4" />
<metadata
id="metadata7">
<rdf:RDF>
<cc:Work
rdf:about="">
<dc:format>image/svg+xml</dc:format>
<dc:type
rdf:resource="http://purl.org/dc/dcmitype/StillImage" />
<dc:title></dc:title>
</cc:Work>
</rdf:RDF>
</metadata>
<g
id="layer1">
"""
path_tpl = """
<path
d="%PATH%"
id="%PATH_ID%"
style="fill:none;stroke:#000000;stroke-width:1px;stroke-linecap:butt;stroke-linejoin:miter;stroke-opacity:1"
"""
svg_footer = "</g></svg>"
# Set up paths
data_root = os.path.join(os.environ['HOME'], 'data')
#modelerc = giss.modele.read_modelerc()
#cmrun = modelerc['CMRUNDIR']
#savedisk = modelerc['SAVEDISK']
ifname = sys.argv[1]
ofname = ifname.replace('.dat', '.svg')
lons, lats = giss.io.noaa.read_coastline(ifname, 1)
out = open(ofname, 'w')
out.write(svg_header)
path_id = 1
points = []
for lon, lat in zip(lons, lats) :
if np.isnan(lon) or np.isnan(lat) :
# Process what we have
if len(points) > 2 :
out.write('\n<path d="')
out.write('m %f,%f L' % (points[0][0], points[0][1]))
for pt in points[1:] :
out.write(' %f,%f' % pt)
out.write('"\n id="path%d"\n' % (path_id))
# out.write('style="fill:none;stroke:#000000;stroke-width:1px;stroke-linecap:butt;stroke-linejoin:miter;stroke-opacity:1"')
out.write(' />\n')
path_id += 1
points = []
else :
lon += 180
lat = 180 - (lat + 90)
points.append((lon, lat))
out.write(svg_footer)
out.close()
# =============================================================
# svg2coastline.py
import os
import sys
import re
# Reads the output of Inkscape's "Plain SVG" format, outputs in NOAA MATLAB coastline format
mainRE = re.compile(r'\s*d=".*"')
lineRE = re.compile(r'\s*d="(m|M)\s*(.*?)"')
fname = sys.argv[1]
lons = []
lats = []
for line in open(fname, 'r') :
# Weed out extraneous lines in the SVG file
match = mainRE.match(line)
if match is None :
continue
match = lineRE.match(line)
# Stop if something is wrong
if match is None :
sys.stderr.write(line)
sys.exit(-1)
type = match.group(1)[0]
spairs = match.group(2).split(' ')
x = 0
y = 0
for spair in spairs :
if spair == 'L' :
type = 'M'
continue
(sdelx, sdely) = spair.split(',')
delx = float(sdelx)
dely = float(sdely)
if type == 'm' :
x += delx
y += dely
else :
x = delx
y = dely
lon = x - 180
lat = 90 - y
print '%f\t%f' % (lon, lat)
print 'nan\tnan'
好的，我想我有一个部分解决方案。
基本思想是 drawcoastlines() 使用的路径按大小/面积排序。这意味着前 N 条路径（对于大多数应用程序）是主要的陆块和湖泊，后面的路径是较小的岛屿和河流。
问题是您想要的前 N 条路径将取决于投影（例如，全球、极地、区域），是否已应用 area_thresh 以及您是否想要湖泊或小岛等。换句话说，您将不得不调整这个每个应用程序。
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
mp = 'cyl'
m = Basemap(resolution='c',projection=mp,lon_0=0,area_thresh=200000)
fill_color = '0.9'
# If you don't want lakes set lake_color to fill_color
m.fillcontinents(color=fill_color,lake_color='white')
# Draw the coastlines, with a thin line and same color as the continent fill.
coasts = m.drawcoastlines(zorder=100,color=fill_color,linewidth=0.5)
# Exact the paths from coasts
coasts_paths = coasts.get_paths()
# In order to see which paths you want to retain or discard you'll need to plot them one
# at a time noting those that you want etc.
for ipoly in xrange(len(coasts_paths)):
print ipoly
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][1] for i in xrange(len(polygon_vertices))]
m.plot(px,py,'k-',linewidth=1)
plt.show()
一旦你知道相关的 ipoly 停止绘图（poly_stop），那么你可以做这样的事情......
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
mproj = ['nplaea','cyl']
mp = mproj[0]
if mp == 'nplaea':
m = Basemap(resolution='c',projection=mp,lon_0=0,boundinglat=30,area_thresh=200000,round=1)
poly_stop = 10
else:
m = Basemap(resolution='c',projection=mp,lon_0=0,area_thresh=200000)
poly_stop = 18
fill_color = '0.9'
# If you don't want lakes set lake_color to fill_color
m.fillcontinents(color=fill_color,lake_color='white')
# Draw the coastlines, with a thin line and same color as the continent fill.
coasts = m.drawcoastlines(zorder=100,color=fill_color,linewidth=0.5)
# Exact the paths from coasts
coasts_paths = coasts.get_paths()
# In order to see which paths you want to retain or discard you'll need to plot them one
# at a time noting those that you want etc.
for ipoly in xrange(len(coasts_paths)):
if ipoly > poly_stop: continue
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][1] for i in xrange(len(polygon_vertices))]
m.plot(px,py,'k-',linewidth=1)
plt.show()
根据我对@sampo-smolander 的评论
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
m = Basemap(resolution='c',projection='robin',lon_0=0)
m.fillcontinents(color='gray',lake_color='white',zorder=2)
coasts = m.drawcoastlines(zorder=1,color='white',linewidth=0)
coasts_paths = coasts.get_paths()
ipolygons = range(83) + [84]
for ipoly in xrange(len(coasts_paths)):
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][1] for i in xrange(len(polygon_vertices))]
if ipoly in ipolygons:
m.plot(px,py,linewidth=0.5,zorder=3,color='black')
else:
m.plot(px,py,linewidth=0.5,zorder=4,color='grey')
plt.savefig('world2.png',dpi=100)
