我的网络服务;
[WebMethod]
public int insertNhanVien(string[] arr)
{
SqlConnection con = new SqlConnection();
// con.ConnectionString = "Data Source=.\\SQLEXPRESS;Initial Catalog=Bai1;Integrated Security=True";
con.ConnectionString = "server=.\\SQLEXPRESS;database=QLNV;uid=sa;pwd=123456";
con.Open();
int n = 0;
for (int i = 0; i < arr.Length; i++)
{
string[] s = arr[i].ToString().Split(',');
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "Insert Into MUser(Ten,Tuoi) values(" + s[0].Replace("'", "''") + "," + s[1] + ")";
cmd.CommandType = CommandType.Text;
cmd.Connection = con;
n = cmd.ExecuteNonQuery();
}
return n;
}
和android中的代码:
private boolean insertNhanVient() {
boolean result = false;
try {
String NAMESPACE ="http://tempuri.org/";
String METHOD_NAME ="insertNhanVien";
String URL ="http://localhost:10829/WebSite/Service.asmx";
String SOAP_ACTIONS = NAMESPACE + "/" + METHOD_NAME;
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
String [] arr =new String[3];
arr[0]="le,12";
arr[1]="hoang,33";
arr[2]="nhung,23";
request.addProperty("arr", arr);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidhttpTranport = new HttpTransportSE(URL);
try {
androidhttpTranport.call(SOAP_ACTIONS, envelope);
} catch (IOException e3) {
result = false;
} catch (XmlPullParserException e3) {
result = false;
}
Object responseBody = null;
try {
responseBody = envelope.getResponse();
String t = responseBody.toString();
if (t.equals("1")) {
result = true;
}
} catch (SoapFault e2) {
result = false;
}
} catch (Exception e) {
result = false;
} finally {
}
return result;
}
为什么显示异常:java.lang.RuntimeException: Cannot serialize: [Ljava.lang.String;@4051d0a0
?