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我正在尝试构建一个查询来检索我，对于每个帖子，其各自的图像、评论、喜欢和收藏的数量。所有这些数据都在单独的关系表中，这些表总是存储帖子的 ID。

但是，当我运行查询时，其他 3 个页面的数据与第一页完全相同。

到目前为止，我已经对此进行了编码

SELECT * FROM
        (SELECT pst.* FROM posts as pst
        LEFT JOIN postcategories as pstcat
        ON pst.id = pstcat.id_post
        WHERE pst.date IS NOT NULL AND pst.date >= '2013-01-01 00:00:00' AND pst.date <= '2013-01-11 00:00:00' ) as res1  
        INNER JOIN
        (SELECT pst.*, count(pstcmt.id) as cmtCount
                        FROM posts as pst
                        LEFT JOIN userpostcomments as pstcmt
                        ON pst.id = pstcmt.id_post 
                        GROUP BY pst.id) as res2 ON res1.id = res2.id
        INNER JOIN
        (SELECT pst.id, count(pstlk.id) as lkCount
                        FROM posts as pst
                        LEFT JOIN userpostlikes as pstlk
                        ON pst.id = pstlk.id_post 
                        GROUP BY pst.id) as res3 ON res1.id = res3.id
        INNER JOIN
        (SELECT pst.id, count(pstfav.id) as favCount
                        FROM posts as pst
                        LEFT JOIN userpostfavorites as pstfav
                        ON pst.id = pstfav.id_post 
                        GROUP BY pst.id) as res4 ON res1.id = res4.id
        INNER JOIN
        (SELECT pst.id, count(pstimg.id) as imgCount
                        FROM posts as pst
                        LEFT JOIN postimages as pstimg
                        ON pst.id = pstimg.id_post 
                        GROUP BY pst.id) as res5 ON res1.id = res5.id

                        WHERE res1.deleted = 0 
                        AND res1.date IS NOT NULL 
                        GROUP BY res1.id
                        ORDER BY res1.date DESC

谢谢

更新：按照建议使用 ORDER BY 更新查询。但是数据镜像问题依然存在

4

1 回答 1

2

也许，这就是你想要的：

SELECT pst.id,
      COALESCE(cmtCount, 0) cmtCount,
      COALESCE(lkCount, 0) lkCount,
      COALESCE(pstfavCount, 0) pstfavCount,
      COALESCE(imgCount , 0) imgCount,
FROM posts as pst
        LEFT JOIN 
           (SELECT id_post, count(id) as cmtCount
                FROM userpostcomments GROUP BY id_post) as cmt
            ON pst.id = cmt.id_post
        LEFT JOIN 
           (SELECT id_post, count(id) as lkCount
                FROM userpostlikes GROUP BY id_post) as lk
            ON pst.id = lk.id_post
        LEFT JOIN 
           (SELECT id_post, count(id) as pstfavCount
                FROM userpostfavorites GROUP BY id_post) as pstfav
            ON pst.id = pstfav.id_post
        LEFT JOIN 
           (SELECT id_post, count(id) as imgCount
                FROM postimages GROUP BY id_post) as img
            ON pst.id = img.id_post
 WHERE pst.deleted = 0 
    AND pst.date >= '2013-01-01 00:00:00'
    AND pst.date <= '2013-01-11 00:00:00'
 ORDER BY pst.date DESC

我想，这个查询更快。

SELECT pst.id,
      COUNT(DISTINCT cmt.id) cmtCount,
      COUNT(DISTINCT lk.id) lkCount,
      COUNT(DISTINCT pstfav.id) pstfavCount,
      COUNT(DISTINCT img.id) imgCount,
FROM posts as pst
        LEFT JOIN userpostcomments cmt
            ON pst.id = cmt.id_post
        LEFT JOIN  userpostlikes lk
            ON pst.id = lk.id_post
        LEFT JOIN userpostfavorites  pstfav
            ON pst.id = pstfav.id_post
        LEFT JOIN postimages  img
            ON pst.id = img.id_post
 WHERE pst.deleted = 0 
    AND pst.date >= '2013-01-01 00:00:00'
    AND pst.date <= '2013-01-11 00:00:00'
 GROUP BY pst.id
 ORDER BY pst.date DESC
于 2013-01-11T11:03:56.487 回答