0 
var Data = {    "1":"United States",
                "2":"United Kingdom",
                "3":"Aruba",
                "4":"United Kingdom",
                "5":"Aruba",
                "6":"Bahrain",
                "7":"United Kingdom",
                "8":"Algeria",
                "9":"Andorra",
                "10":"American Samoa"
}
var IdKeyValuePair = [{"DropD1":Data},{"DropD2":Data},{"DropD3":Data},{"DropD4":Data}];
var obj= {
            id           : IdKeyValuePair,
            MultiColuumn : true,
            Checkbox     : true,
            Pagination   : false,
            max_height   : 400

         };

我想打印 DropD1、DropD2 的名称。我正在尝试这种方式。但我无法做到这一点..

var idName = [],i;
idLen = obj.id.length;
for(i=0;i<idLen;i++){
    idName[i] = ''+obj.id[i];
    console.log(idName[i]);
}

我得到了 DropD1，DropD2 .. 但问题是它是对象形式，所以我如何将它转换为字符串......我想要一个结果是这样的格式......

for(i=0;i<idLen;i++){
   console.log(idName[i]);
}

字符串格式的预期输出不在对象中：

滴D1 滴D2 滴D3

4

4 回答 4

0

试试这个。它对我有用

var IdKeyValuePair = [{ "DropD1": Data["1"] }, { "DropD2": Data["2"] }, { "DropD3": Data["3"]}, { "DropD4": Data["4"]}]; so on and so forth.
于 2013-01-11T07:51:35.677 回答
0

我得到了一种使用浏览器字符串化属性的解决方案::

var jsonobj={"name":"George", "age":29, "friends":["John", "Sarah", "Albert"]}
var jsonstr=JSON.stringify(jsonobj)
alert(typeof jsonstr) //string

您可以通过以下方式将其转换为 javascript 对象::

var jsonstr='{"name":"George", "age":29, "friends":["John", "Sarah", "Albert"]}'
var george=JSON.parse(jsonstr) //convert JSON string into object
alert(george.age)

有关 json 的更多信息，请参阅以下链接，

http://www.javascriptkit.com/jsref/json.shtml

于 2013-01-11T07:52:36.380 回答
0

试试这个

var idName = [],i;
idLen = obj.id.length;
for(i=0;i<idLen;i++){
    idName[i] = obj.id[i];
}
console.log(idName.join(" "));
于 2013-01-11T08:01:11.177 回答
0

试试这个：

  var Data = {    "1":"United States",
                  "2":"United Kingdom",
                  "3":"Aruba",
                  "4":"United Kingdom",
                  "5":"Aruba",
                  "6":"Bahrain",
                  "7":"United Kingdom",
                  "8":"Algeria",
                  "9":"Andorra",
                  "10":"American Samoa"
  }
  var IdKeyValuePair = [{"DropD1":Data},{"DropD2":Data},{"DropD3":Data},{"DropD4":Data}];
  var obj= {
              id           : IdKeyValuePair,
              MultiColuumn : true,
              Checkbox     : true,
              Pagination   : false,
              max_height   : 400

           };

  var idName = [],i;
  idLen = obj.id.length;
  for(i=0;i<idLen;i++){
    idName[i] = obj.id[i];
    console.info(JSON.stringify(idName[i]));
  }

您通过向对象添加空字符串（“”+对象）不必要地将对象转换为字符串

于 2013-01-11T08:02:35.593 回答