77

前提:

在玩了一些可变参数模板之后,我意识到实现任何稍微超出琐碎的元编程任务的事情很快就会变得非常麻烦。特别是,我发现自己希望有一种方法可以对参数包执行通用操作,例如以类似方式的iterate split loop等等std::for_each

在观看了来自 C++ 和 Beyond 2012的 Andrei Alexandrescu的关于对 C++ 的可取性(从D 编程语言static if中借用的结构)的讲座之后,我感觉某种东西也会派上用场 - 我觉得更多这些结构可以带来好处。static forstatic

所以我开始想知道是否有一种方法可以为可变参数模板函数(伪代码)的参数包实现类似的功能:

template<typename... Ts>
void my_function(Ts&&... args)
{
    static for (int i = 0; i < sizeof...(args); i++) // PSEUDO-CODE!
    {
        foo(nth_value_of<i>(args));
    }
}

这会在编译时被翻译成这样的:

template<typename... Ts>
void my_function(Ts&&... args)
{
    foo(nth_value_of<0>(args));
    foo(nth_value_of<1>(args));
    // ...
    foo(nth_value_of<sizeof...(args) - 1>(args));
}

原则上,static_for将允许更精细的处理:

template<typename... Ts>
void foo(Ts&&... args)
{
    constexpr s = sizeof...(args);

    static for (int i = 0; i < s / 2; i++)
    {
        // Do something
        foo(nth_value_of<i>(args));
    }

    static for (int i = s / 2; i < s; i++)
    {
        // Do something different
        bar(nth_value_of<i>(args));
    }
}

或者像这样一个更具表现力的成语:

template<typename... Ts>
void foo(Ts&&... args)
{
    static for_each (auto&& x : args)
    {
        foo(x);
    }
}

相关工作:

我在网上做了一些搜索,发现确实存在一些东西:

  • 此链接描述了如何将参数包转换为 Boost.MPL 向量,但这只是实现目标的一半(如果不是更少);
  • 这个关于 SO的问题似乎需要一个类似且稍微相关的元编程功能(将参数包分成两半) - 实际上,有几个关于 SO 的问题似乎与这个问题有关,但我没有一个答案已阅读,恕我直言,令人满意地解决了它;
  • Boost.Fusion定义了将参数包转换为tuple的算法,但我更喜欢:
    1. 不要创建不必要的临时变量来保存可以(并且应该)完美地转发给某些通用算法的参数;
    2. 有一个小型的、独立的库来做到这一点,而 Boost.Fusion 可能包含比解决这个问题所需的更多的东西。

问题:

有没有一种相对简单的方法,可能通过一些模板元编程来实现我正在寻找的东西,而不会受到现有方法的限制?

4

5 回答 5

65

由于我对自己的发现不满意,因此我尝试自己制定解决方案,并最终编写了一个小型库,该库允许在参数包上制定通用操作。我的解决方案具有以下特点:

  • 允许迭代参数包的所有或部分元素,可能通过计算它们在包上的索引来指定;
  • 允许将参数包的计算部分转发到可变函子;
  • 只需要包含一个相对较短的头文件;
  • 广泛使用完美转发以允许大量内联并避免不必要的复制/移动以最小化性能损失;
  • 迭代算法的内部实现依赖于空基类优化来最小化内存消耗;
  • 扩展和适应很容易(相对而言,考虑到它是模板元编程)。

我将首先展示该库可以做什么然后发布它的实现

用例

这是一个如何使用for_each_in_arg_pack()函数迭代包的所有参数并将输入中的每个参数传递给某些客户端提供的仿函数的示例(当然,如果参数包包含值,仿函数必须具有通用调用运算符异构类型):

// Simple functor with a generic call operator that prints its input. This is used by the
// following functors and by some demonstrative test cases in the main() routine.
struct print
{
    template<typename T>
    void operator () (T&& t)
    {
        cout << t << endl;
    }
};

// This shows how a for_each_*** helper can be used inside a variadic template function
template<typename... Ts>
void print_all(Ts&&... args)
{
    for_each_in_arg_pack(print(), forward<Ts>(args)...);
}

上面的print仿函数也可以用于更复杂的计算。特别是,以下是如何迭代包中参数的子集(在本例中为sub-range):

// Shows how to select portions of an argument pack and 
// invoke a functor for each of the selected elements
template<typename... Ts>
void split_and_print(Ts&&... args)
{
    constexpr size_t packSize = sizeof...(args);
    constexpr size_t halfSize = packSize / 2;

    cout << "Printing first half:" << endl;
    for_each_in_arg_pack_subset(
        print(), // The functor to invoke for each element
        index_range<0, halfSize>(), // The indices to select
        forward<Ts>(args)... // The argument pack
        );

    cout << "Printing second half:" << endl;
    for_each_in_arg_pack_subset(
        print(), // The functor to invoke for each element
        index_range<halfSize, packSize>(), // The indices to select
        forward<Ts>(args)... // The argument pack
        );
}

有时,人们可能只想将参数包的一部分转发给其他可变参数函子,而不是遍历其元素并将每个元素单独传递给非可变参数函子。这是forward_subpack()算法允许做的事情:

// Functor with variadic call operator that shows the usage of for_each_*** 
// to print all the arguments of a heterogeneous pack
struct my_func
{
    template<typename... Ts>
    void operator ()(Ts&&... args)
    {
        print_all(forward<Ts>(args)...);
    }
};

// Shows how to forward only a portion of an argument pack 
// to another variadic functor
template<typename... Ts>
void split_and_print(Ts&&... args)
{
    constexpr size_t packSize = sizeof...(args);
    constexpr size_t halfSize = packSize / 2;

    cout << "Printing first half:" << endl;
    forward_subpack(my_func(), index_range<0, halfSize>(), forward<Ts>(args)...);

    cout << "Printing second half:" << endl;
    forward_subpack(my_func(), index_range<halfSize, packSize>(), forward<Ts>(args)...);
}

对于更具体的任务,当然可以通过索引包中的特定参数来检索它们。这是nth_value_of()函数允许做的事情,连同它的助手first_value_of()last_value_of()

// Shows that arguments in a pack can be indexed
template<unsigned I, typename... Ts>
void print_first_last_and_indexed(Ts&&... args)
{
    cout << "First argument: " << first_value_of(forward<Ts>(args)...) << endl;
    cout << "Last argument: " << last_value_of(forward<Ts>(args)...) << endl;
    cout << "Argument #" << I << ": " << nth_value_of<I>(forward<Ts>(args)...) << endl;
}

另一方面,如果参数包是同质的(即所有参数都具有相同的类型),则下面的公式可能更可取。元函数允许确定参数包中的is_homogeneous_pack<>所有类型是否都是同质的,主要用于static_assert()语句中:

// Shows the use of range-based for loops to iterate over a
// homogeneous argument pack
template<typename... Ts>
void print_all(Ts&&... args)
{
    static_assert(
        is_homogeneous_pack<Ts...>::value, 
        "Template parameter pack not homogeneous!"
        );

    for (auto&& x : { args... })
    {
        // Do something with x...
    }

    cout << endl;
}

最后,由于lambda只是函子的语法糖,它们也可以与上述算法结合使用;但是,在C++ 支持泛型 lambda之前,这仅适用于同构参数包。以下示例还显示了homogeneous-type<>元函数的用法,它返回同质包中所有参数的类型:

 // ...
 static_assert(
     is_homogeneous_pack<Ts...>::value, 
     "Template parameter pack not homogeneous!"
     );
 using type = homogeneous_type<Ts...>::type;
 for_each_in_arg_pack([] (type const& x) { cout << x << endl; }, forward<Ts>(args)...);

这基本上是图书馆允许做的事情,但我相信它甚至可以扩展到执行更复杂的任务。

执行

现在是实现,这本身有点棘手,所以我将依靠注释来解释代码并避免使这篇文章太长(也许它已经是):

#include <type_traits>
#include <utility>

//===============================================================================
// META-FUNCTIONS FOR EXTRACTING THE n-th TYPE OF A PARAMETER PACK

// Declare primary template
template<int I, typename... Ts>
struct nth_type_of
{
};

// Base step
template<typename T, typename... Ts>
struct nth_type_of<0, T, Ts...>
{
    using type = T;
};

// Induction step
template<int I, typename T, typename... Ts>
struct nth_type_of<I, T, Ts...>
{
    using type = typename nth_type_of<I - 1, Ts...>::type;
};

// Helper meta-function for retrieving the first type in a parameter pack
template<typename... Ts>
struct first_type_of
{
    using type = typename nth_type_of<0, Ts...>::type;
};

// Helper meta-function for retrieving the last type in a parameter pack
template<typename... Ts>
struct last_type_of
{
    using type = typename nth_type_of<sizeof...(Ts) - 1, Ts...>::type;
};

//===============================================================================
// FUNCTIONS FOR EXTRACTING THE n-th VALUE OF AN ARGUMENT PACK

// Base step
template<int I, typename T, typename... Ts>
auto nth_value_of(T&& t, Ts&&... args) ->
    typename std::enable_if<(I == 0), decltype(std::forward<T>(t))>::type
{
    return std::forward<T>(t);
}

// Induction step
template<int I, typename T, typename... Ts>
auto nth_value_of(T&& t, Ts&&... args) ->
    typename std::enable_if<(I > 0), decltype(
        std::forward<typename nth_type_of<I, T, Ts...>::type>(
            std::declval<typename nth_type_of<I, T, Ts...>::type>()
            )
        )>::type
{
    using return_type = typename nth_type_of<I, T, Ts...>::type;
    return std::forward<return_type>(nth_value_of<I - 1>((std::forward<Ts>(args))...));
}

// Helper function for retrieving the first value of an argument pack
template<typename... Ts>
auto first_value_of(Ts&&... args) ->
    decltype(
        std::forward<typename first_type_of<Ts...>::type>(
            std::declval<typename first_type_of<Ts...>::type>()
            )
        )
{
    using return_type = typename first_type_of<Ts...>::type;
    return std::forward<return_type>(nth_value_of<0>((std::forward<Ts>(args))...));
}

// Helper function for retrieving the last value of an argument pack
template<typename... Ts>
auto last_value_of(Ts&&... args) ->
    decltype(
        std::forward<typename last_type_of<Ts...>::type>(
            std::declval<typename last_type_of<Ts...>::type>()
            )
        )
{
    using return_type = typename last_type_of<Ts...>::type;
    return std::forward<return_type>(nth_value_of<sizeof...(Ts) - 1>((std::forward<Ts>(args))...));
}

//===============================================================================
// METAFUNCTION FOR COMPUTING THE UNDERLYING TYPE OF HOMOGENEOUS PARAMETER PACKS

// Used as the underlying type of non-homogeneous parameter packs
struct null_type
{
};

// Declare primary template
template<typename... Ts>
struct homogeneous_type;

// Base step
template<typename T>
struct homogeneous_type<T>
{
    using type = T;
    static const bool isHomogeneous = true;
};

// Induction step
template<typename T, typename... Ts>
struct homogeneous_type<T, Ts...>
{
    // The underlying type of the tail of the parameter pack
    using type_of_remaining_parameters = typename homogeneous_type<Ts...>::type;

    // True if each parameter in the pack has the same type
    static const bool isHomogeneous = std::is_same<T, type_of_remaining_parameters>::value;

    // If isHomogeneous is "false", the underlying type is the fictitious null_type
    using type = typename std::conditional<isHomogeneous, T, null_type>::type;
};

// Meta-function to determine if a parameter pack is homogeneous
template<typename... Ts>
struct is_homogeneous_pack
{
    static const bool value = homogeneous_type<Ts...>::isHomogeneous;
};

//===============================================================================
// META-FUNCTIONS FOR CREATING INDEX LISTS

// The structure that encapsulates index lists
template <unsigned... Is>
struct index_list
{
};

// Collects internal details for generating index ranges [MIN, MAX)
namespace detail
{
    // Declare primary template for index range builder
    template <unsigned MIN, unsigned N, unsigned... Is>
    struct range_builder;

    // Base step
    template <unsigned MIN, unsigned... Is>
    struct range_builder<MIN, MIN, Is...>
    {
        typedef index_list<Is...> type;
    };

    // Induction step
    template <unsigned MIN, unsigned N, unsigned... Is>
    struct range_builder : public range_builder<MIN, N - 1, N - 1, Is...>
    {
    };
}

// Meta-function that returns a [MIN, MAX) index range
template<unsigned MIN, unsigned MAX>
using index_range = typename detail::range_builder<MIN, MAX>::type;

//===============================================================================
// CLASSES AND FUNCTIONS FOR REALIZING LOOPS ON ARGUMENT PACKS

// Implementation inspired by @jogojapan's answer to this question:
// http://stackoverflow.com/questions/14089637/return-several-arguments-for-another-function-by-a-single-function

// Collects internal details for implementing functor invocation
namespace detail
{
    // Functor invocation is realized through variadic inheritance.
    // The constructor of each base class invokes an input functor.
    // An functor invoker for an argument pack has one base class
    // for each argument in the pack

    // Realizes the invocation of the functor for one parameter
    template<unsigned I, typename T>
    struct invoker_base
    {
        template<typename F, typename U>
        invoker_base(F&& f, U&& u) { f(u); }
    };

    // Necessary because a class cannot inherit the same class twice
    template<unsigned I, typename T>
    struct indexed_type
    {
        static const unsigned int index = I;
        using type = T;
    };

    // The functor invoker: inherits from a list of base classes.
    // The constructor of each of these classes invokes the input
    // functor with one of the arguments in the pack.
    template<typename... Ts>
    struct invoker : public invoker_base<Ts::index, typename Ts::type>...
    {
        template<typename F, typename... Us>
        invoker(F&& f, Us&&... args)
            :
            invoker_base<Ts::index, typename Ts::type>(std::forward<F>(f), std::forward<Us>(args))...
        {
        }
    };
}

// The functor provided in the first argument is invoked for each
// argument in the pack whose index is contained in the index list
// specified in the second argument
template<typename F, unsigned... Is, typename... Ts>
void for_each_in_arg_pack_subset(F&& f, index_list<Is...> const& i, Ts&&... args)
{
    // Constructors of invoker's sub-objects will invoke the functor.
    // Note that argument types must be paired with numbers because the
    // implementation is based on inheritance, and one class cannot
    // inherit the same base class twice.
    detail::invoker<detail::indexed_type<Is, typename nth_type_of<Is, Ts...>::type>...> invoker(
        f,
        (nth_value_of<Is>(std::forward<Ts>(args)...))...
        );
}

// The functor provided in the first argument is invoked for each
// argument in the pack
template<typename F, typename... Ts>
void for_each_in_arg_pack(F&& f, Ts&&... args)
{
    for_each_in_arg_pack_subset(f, index_range<0, sizeof...(Ts)>(), std::forward<Ts>(args)...);
}

// The functor provided in the first argument is given in input the
// arguments in whose index is contained in the index list specified
// as the second argument.
template<typename F, unsigned... Is, typename... Ts>
void forward_subpack(F&& f, index_list<Is...> const& i, Ts&&... args)
{
    f((nth_value_of<Is>(std::forward<Ts>(args)...))...);
}

// The functor provided in the first argument is given in input all the
// arguments in the pack.
template<typename F, typename... Ts>
void forward_pack(F&& f, Ts&&... args)
{
    f(std::forward<Ts>(args)...);
}

结论

当然,即使我对这个问题提供了自己的答案(实际上是因为这个事实),我很想知道是否存在我错过的替代或更好的解决方案——除了“相关作品”部分中提到的那些的问题。

于 2013-01-10T15:19:29.680 回答
10

让我根据讨论发布这段代码:

#include <initializer_list>
#define EXPAND(EXPR) std::initializer_list<int>{((EXPR),0)...}

// Example of use:
#include <iostream>
#include <utility>

void print(int i){std::cout << "int: " << i << '\n';}
int print(double d){std::cout << "double: " << d << '\n';return 2;}

template<class...T> void f(T&&...args){
  EXPAND(print(std::forward<T>(args)));
}

int main(){
  f();
  f(1,2.,3);
}

我检查了生成的代码,g++ -std=c++11 -O1main包含 3 次调用print,没有扩展助手的踪迹。

于 2013-01-10T19:17:25.950 回答
5

使用枚举解决方案(ala Python)。

用法:

void fun(int i, size_t index, size_t size) {
    if (index != 0) {
        std::cout << ", ";
    }

    std::cout << i;

    if (index == size - 1) {
        std::cout << "\n";
    }
} // fun

enumerate(fun, 2, 3, 4);

// Expected output: "2, 3, 4\n"
// check it at: http://liveworkspace.org/code/1cydbw$4

代码:

// Fun: expects a callable of 3 parameters: Arg, size_t, size_t
// Arg: forwarded argument
// size_t: index of current argument
// size_t: number of arguments
template <typename Fun, typename... Args, size_t... Is>
void enumerate_impl(Fun&& fun, index_list<Is...>, Args&&... args) {
    std::initializer_list<int> _{
        (fun(std::forward<Args>(args), Is, sizeof...(Is)), 0)...
    };
    (void)_; // placate compiler, only the side-effects interest us
}

template <typename Fun, typename... Args>
void enumerate(Fun&& fun, Args&&... args) {
    enumerate_impl(fun,
                   index_range<0, sizeof...(args)>(),
                   std::forward<Args>(args)...);
}

范围生成器(从您的解决方案中窃取):

// The structure that encapsulates index lists
template <size_t... Is>
struct index_list
{
};

// Collects internal details for generating index ranges [MIN, MAX)
namespace detail
{
    // Declare primary template for index range builder
    template <size_t MIN, size_t N, size_t... Is>
    struct range_builder;

    // Base step
    template <size_t MIN, size_t... Is>
    struct range_builder<MIN, MIN, Is...>
    {
        typedef index_list<Is...> type;
    };

    // Induction step
    template <size_t MIN, size_t N, size_t... Is>
    struct range_builder : public range_builder<MIN, N - 1, N - 1, Is...>
    {
    };
}

// Meta-function that returns a [MIN, MAX) index range
template<size_t MIN, size_t MAX>
using index_range = typename detail::range_builder<MIN, MAX>::type;
于 2013-02-13T16:56:56.050 回答
0

在阅读了一些其他帖子并修改了一段时间后,我想出了以下内容(有点类似于上面,但实现有点不同)。我使用 Visual Studio 2013 编译器编写了这个。

使用 lambda 表达式的用法 -

static_for_each()(
    [](std::string const& str)
    {
        std::cout << str << std::endl;
    }, "Hello, ", "Lambda!");

使用 lambda 的缺点是参数必须与 lambda 的参数列表中声明的类型相同。这意味着它只适用于一种类型。如果要使用模板化函数,可以使用下一个示例。

使用结构包装函子的用法 -

struct print_wrapper
{
    template <typename T>
    void operator()(T&& str)
    {
        std::cout << str << " ";
    }
};

// 
// A little test object we can use.
struct test_object
{
    test_object() : str("I'm a test object!") {}
    std::string str;
};

std::ostream& operator<<(std::ostream& os, test_object t)
{
    os << t.str;
    return os;
}

//
// prints: "Hello, Functor! 1 2 I'm a test object!"
static_for_each()(print_wrapper(), "Hello,", "Functor!", 1, 2.0f, test_object());

这允许您传入任何您想要的类型并使用仿函数对它们进行操作。我发现这很干净,可以很好地满足我的需求。您也可以将它与这样的函数参数包一起使用 -

template <typename T, typename... Args>
void call(T f, Args... args)
{
    static_for_each()(f, args...);
}

call(print_wrapper(), "Hello", "Call", "Wrapper!");

这是实现 -

// 
// Statically iterate over a parameter pack 
// and call a functor passing each argument.
struct static_for_each
{
private:
    // 
    // Get the parameter pack argument at index i.
    template <size_t i, typename... Args>
    static auto get_arg(Args&&... as) 
    -> decltype(std::get<i>(std::forward_as_tuple(std::forward<Args>(as)...)))
    {
        return std::get<i>(std::forward_as_tuple(std::forward<Args>(as)...));
    }

    //
    // Recursive template for iterating over 
    // parameter pack and calling the functor.
    template <size_t Start, size_t End>
    struct internal_static_for
    {
        template <typename Functor, typename... Ts>
        void operator()(Functor f, Ts&&... args)
        {
            f(get_arg<Start>(args...));
            internal_static_for<Start + 1, End>()(f, args...);
        }
    };

    //
    // Specialize the template to end the recursion.
    template <size_t End>
    struct internal_static_for<End, End>
    {
        template <typename Functor, typename... Ts>
        void operator()(Functor f, Ts&&... args){}
    };

public:
    // 
    // Publically exposed operator()(). 
    // Handles template recursion over parameter pack.
    // Takes the functor to be executed and a parameter 
    // pack of arguments to pass to the functor, one at a time.
    template<typename Functor, typename... Ts>
    void operator()(Functor f, Ts&&... args)
    {
        // 
        // Statically iterate over parameter
        // pack from the first argument to the
        // last, calling functor f with each 
        // argument in the parameter pack.
        internal_static_for<0u, sizeof...(Ts)>()(f, args...);
    }
};

希望人们觉得这很有用:-)

于 2014-11-07T21:56:06.660 回答
0

... 符号确实有一些有趣的选项,例如:

template<typename T>
int print(const T& x) {
  std::cout << "<" << x << ">";
  return 0;
}

void pass(...) {}

template<typename... TS>
void printall(TS... ts){
  pass(print(ts)...);
}

不幸的是,我不知道有什么方法可以强制执行调用打印函数的顺序(相反,在我的编译器上)。请注意, print 需要返回一些东西。

如果您不关心订单,这个技巧会很有用。

于 2013-01-15T06:46:26.290 回答