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我有一个返回多行字符串的方法..我已经用参数和不带参数进行了测试..没有参数（带常量）它可以工作..这里是函数

public string AppComments()
        {
           string teststring = @"Nelly Thomas (Approve) 12/27/2012 8:50 PM - 12/27/2012 8:52 PM
                               (Nelly Thomas) LazyApproval by nelly.thomas@joshworld.local Approved

                                Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, 
                                when an unknown printer took a galley of type and scrambled it to make a type specimen book";

              Regex reg = new Regex(@"(.+)\(.+\)\s((\d\d\/){2}\d{4}\s\d{1,2}:\d\d\s\w\w)\s-\s.+[\n|\r].+[\n|\r]{2}((?:.|\n)+)", RegexOptions.IgnoreCase | RegexOptions.Multiline);

              string returnstring = reg.Match(teststring).Groups[1].Value + reg.Match(teststring).Groups[2].Value + reg.Match(teststring).Groups[4].Value.ToString();

            return returnstring;
        }

但是当我传递以下文本时，它永远不会返回任何值..它显示为空白..我猜我在方法内部传递的值没有多行文字？

Nelly Thomas (Approve) 12/27/2012 8:50 PM - 12/27/2012 8:52 PM
(Nelly Thomas) LazyApproval by nelly.thomas@joshworld.local Approved

Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, 
when an unknown printer took a galley of type and scrambled it to make a type specimen book

这是带参数的函数

public string AppComments(string mystring)
        {

              Regex reg = new Regex(@"(.+)\(.+\)\s((\d\d\/){2}\d{4}\s\d{1,2}:\d\d\s\w\w)\s-\s.+[\n|\r].+[\n|\r]{2}((?:.|\n)+)", RegexOptions.IgnoreCase | RegexOptions.Multiline);

              string returnstring = reg.Match(mystring).Groups[1].Value + reg.Match(mystring).Groups[2].Value + reg.Match(mystring).Groups[4].Value.ToString();

            return returnstring;
        }
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1 回答 1

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尝试使用$作为正则表达式中行尾的谓词。如果您不使用 ^ 和 $，RegexOptions.Multiline 将毫无意义

另一种方法：尝试将行尾标记为可选：

Regex reg = new Regex(@"(.+)\(.+\)\s((\d\d\/){2}\d{4}\s\d{1,2}:\d\d\s\w\w)\s-\s.+[\n|\r]??.+([\n|\r]{2})??((?:.|\n)+)", RegexOptions.IgnoreCase);

于 2013-01-10T11:40:52.643 回答