ios - IOS 追加帖子请求

Question

我想输入如下内容：

address[address1] = adsads
address[address2] = dsadsad
address[address3] = vadsa

我知道如果这是简单的帖子，我可以这样做：

url?address1=adsads&address2=dsadsa

但是如果我想在帖子中使它成为地址对象（数组），我该如何在IOS中制作它？

Answer 1

想过使用字典（如果我这样做的话可能会起作用），但只是被告知我可以像这样传递 url：

url?address[addres1]=dsadsa&address[address2]=dsadsa

因为浏览器和服务器不会自动对其进行编码并将 [] 作为特殊字符读取。

愚蠢的问题，谢谢大家的回答

Answer 2

嗯，你可以用字典。

NSMutableDictionary * argDict = [NSMutableDictinary new];
[argDict setObject:@"John" forKey:@"name"];
[argDict setObject:@"26" forKey:@"age"];
...
NSMutableString * url = [NSMutableString stringWithCapacity:30];
[url appendString:@"http://?"];
BOOL isFirstArg = YES;
for (NSString * key in [argDict allKeys]) {
    if (isFirstArg) {
        [url appendFormat:@"%@=%@", key, [argDict objectForKey:key]];
        isFirstArg = NO;
        continue;
    }
    [url appendFormat:@"&%@=%@", key, [argDict objectForKey:key]];
}

注意：我想你也可以找到一种更好的方法来处理第一个 arg :)

Answer 3

假设 address1,address2,address3, ... 等是整数，您可以使用 switch 如下所示：

for (int i = 0; i < addressX; i++)
{
     switch(i)
     {
         case address1:
              address[i]=adsads;
              break;
         case address2:
              address[i]=aoao;
              break;
         case address3:
              address[i]=olol;
              break;
         case address4:
              address[i]=dodo;
              break;
         case address5:
              address[i]=lolo;
              break;
     }
}