mysql - MYSQL 函数

Question

我有一张由podcasts我做过的表格、歌曲、艺术家、标题混合编号日期等组成的表格。我正在使用具有单独方法的类来单独显示它们

我的问题是，你如何得到desc行？像这样(mix_number is an int)

 select mix_name, date where mix_number = MAX(mix_number) limit 1 //1st query

 select mix_name, date where mix_number = MAX(mix_number - 1)//this would be the second query

 select mix_name, date where mix_number = MAX(mix_number - 2)//3rd query

我不想where clause用数字硬编码，因为我希望它随着我添加更多而更新。

我真的在问是MAX(mix_number)还是MAX(mix_number-1)适当的？我不能让它以这种方式工作

我希望这是可以理解的。我在方法中有其他疑问，但这里的答案也会解决它们。

Answer 1

select mix_name, date 
FROM tableName
where mix_number = (SELECT MAX(mix_number) FROM tableName)
LIMIT 1

或者

select mix_name, date 
FROM tableName
where mix_number = (SELECT MAX(mix_number) FROM tableName) - 1
LIMIT 1

Answer 2

第一个查询：

SELECT mix_name, date
FROM table
ORDER BY mix_number DESC
LIMIT 1, 0

第二个查询：

SELECT mix_name, date
FROM table
ORDER BY mix_number DESC
LIMIT 1, 1

如果您想要来自同一查询的所有行：

SELECT mix_name, date
FROM table
ORDER BY mix_number DESC

如果您想更精确地对具有相同 mix_number 的行进行排序：

SELECT mix_name, date
FROM table
ORDER BY mix_number DESC, date DESC

Answer 3

你需要一个ORDER BY子句。

select mix_name, date order by mix_number desc

添加LIMIT 0, 1将是您的第一个查询。LIMIT 1, 1将是第二个。等等