1

这是我的 rating.php（html 代码）

<input type="radio" name="selectThree" value="1">
<input type="radio" name="selectThree" value="2">
<input type="radio" name="selectThree" value="3">
<input type="radio" name="selectThree" value="4">
<input type="radio" name="selectThree" value="5">

<input type="radio" name="selectTwo" value="1">
<input type="radio" name="selectTwo" value="2">
<input type="radio" name="selectTwo" value="3">
<input type="radio" name="selectTwo" value="4">
<input type="radio" name="selectTwo" value="5">

<input type="radio" name="selectOne" value="1">
<input type="radio" name="selectOne" value="2">
<input type="radio" name="selectOne" value="3">
<input type="radio" name="selectOne" value="4">
<input type="radio" name="selectOne" value="5">

因此，当用户选择该值时，它将在此处生成以下代码以插入数据库：

<?php
include_once "mysqli.connect.php";
include_once "config.php";

if(isset($_POST['Click']))      
{

$rating = explode($_POST['selectOne'], $_POST['selectTwo'], $_POST['selectThree']);
$_SESSION['commentInput'] = array();
$_SESSION['commentInput'][] = $_POST['comment'][0];
$_SESSION['commentInput'][] = $_POST['comment'][1];
$_SESSION['commentInput'][] = $_POST['comment'][2];

if(isset($_REQUEST["comment"]))
{

$merge = array_combine ($_SESSION['product'],$_SESSION['commentInput']);
foreach($merge as $key => $value)
{

$sqlComment = "INSERT into comment (comment, product) VALUES ('".$value."', '".$key."')";
$result = $mysqli->query($sqlComment);
}

echo"<script type='text/javascript'>alert('Thank you for your comment!' )</script>";
}

else
{

echo "<script type='text/javascript'>alert('Please comment!')</script>";    
}   

}

我想这样存储在mysql数据库中->

product|rating
--------------
shirt  | 2
pants  | 3
dress  | 5

但现在它像这样存储：

product|rating
--------------
shirt  | Array
pants  | Array
dress  | Array

在我使用这个之后->

$rating = explode($_POST['selectOne'], $_POST['selectTwo'], $_POST['selectThree']);

//mysql
$sqlRating = "INSERT into ratings (product, rating) VALUES ('".$key."', '".$rating."')";
$result = $mysqli->query($sqlRating);

如何将值存储到 mysql 中？请帮忙谢谢！

4

3 回答 3

1

你$rating是一个数组

你应该存储这样的值$rating[0]or $rating[1]，$rating[2]所以要像这样存储它们，你可以在 php 中管理它们，选择或单击按钮，然后将它们存储在你的表中

于 2013-01-09T08:14:44.830 回答
0

尝试将它放在类似这样的 foreach 循环中。

// create an array here that contains the key and the rating key=>rating and save it to $ratings array.

foreach($ratings as $key=>$rating){

   //mysql
   $sqlRating = "INSERT into ratings (product, rating) VALUES ('".$key."', '".$rating."')";
   $result = $mysqli->query($sqlRating);
}

顺便说一句，这里是发布单选按钮值的教程http://www.homeandlearn.co.uk/php/php4p10.html

更新： 假设 $key 包含产品数组。（例如 array('shirt', 'pants', 'jacket') 并且它被映射到单选按钮的值。

'shirt' => $_POST['selectOne'];
'pants' => $_POST['selectTwo'];
'jacket' => $_POST['selectThree'];

我们可以为 $key 和 $ratings 创建一个名为 $prod_ratings 的数组

$ratings = array($_POST['selectOne'], $_POST['selectTwo'], $_POST['selectThree']);
$prod_ratings = array_combine($key, $ratings);

然后通过以下方式将数组的值插入数据库：

foreach($prod_ratings as $key=>$rating){

   //mysql
   $sqlRating = "INSERT into ratings (product, rating) VALUES ('".$key."', '".$rating."')";
   $result = $mysqli->query($sqlRating);
}
于 2013-01-09T08:17:29.310 回答
0

使用 implode 将它们以逗号分隔的方式放置：

$rating = explode($_POST['selectOne'], $_POST['selectTwo'], $_POST['selectThree']);

//mysql
$sqlRating = "INSERT into ratings (product, rating) VALUES ('".$key."', '".implode(",",$rating)."')";
$result = $mysqli->query($sqlRating);

稍后您应该能够在过滤数据时使用 find_in_set 查看该列。

于 2013-01-09T09:13:25.867 回答