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Itunes 为我提供了一个我不习惯使用的导出 xml 结构（请参阅 xml 代码）：

<?xml version="1.0" encoding="UTF-8"?>
<plist version="1.0">
<dict>
    <dict>
        <key>68768</key>
        <dict>
            <key>Track ID</key><integer>68768</integer>
            <key>Name</key><string>ABBA Medley</string>
            <key>Artist</key><string>Party All Stars</string>           
            <key>Disc Number</key><integer>1</integer>
            <key>Track Number</key><integer>17</integer>
            <key>Persistent ID</key><string>B121116C66BE0F4B</string>
        </dict>
        <key>68781</key>
        <dict>
            <key>Track ID</key><integer>68781</integer>
            <key>Name</key><string>Afflitto</string>
            <key>Artist</key><string>Fiocco</string>
            <key>Disc Number</key><integer>1</integer>
            <key>Track Number</key><integer>9</integer>
            <key>Persistent ID</key><string>5D09837999591307</string>
        </dict>
        <key>68793</key>
        <dict>
            <key>Track ID</key><integer>68793</integer>
            <key>Name</key><string>Agadou</string>
            <key>Artist</key><string>Saradossa Band</string>
            <key>Disc Number</key><integer>1</integer>
            <key>Track Number</key><integer>4</integer>
            <key>Persistent ID</key><string>4DFFF3C3498C02B4</string>
        </dict>
    </dict>
</dict>
</plist>

我的目标是在 c# 中使用 LinqToXml 尽可能获得以下数组：

17  ABBA Medley  B121116C66BE0F4B
9   Afflitto     5D09837999591307
4   Agadou       4DFFF3C3498C02B4

这甚至可能吗？
我写了一些基本的 c# 代码，但在路上一个闪电击中了我......

XDocument doc = XDocument.Load(iTunesXmlFile);
var linqtoxml = from node in doc.Descendants("dict") select node; // ooo Boy :(

foreach (var dict in linqtoxml)
{
   // and lightning bolt again...
}

Ps：很明显，我无法更改xml结构。
Pps：我知道，这是一个清理 iTunes XML 版本，但基本概念是作为案例研究提出的。

4

1 回答 1

0

我能想到的最佳解决方案如下：

List<Track> MyTrackList = new List<Track>();

public class Track 
{
    public int TrackNumber { get; set; }
    public string Name { get; set; }
    public string PersistentID { get; set; }
} 

XDocument doc = XDocument.Load(@"thexmlfile.xml");
var linqtoxml = from element in doc.Descendants("plist").Descendants("dict").Descendants("dict").Descendants("dict")
                select element;

foreach (var dict in linqtoxml)
{
    try
    {
        string myTrackNumber = dict.Descendants("key").Where(key => key.Value == "Track Number").Select(x => x.NextNode).SingleOrDefault().ToString(); 
        string myName = dict.Descendants("key").Where(key => key.Value == "Name").Select(x => x.NextNode).SingleOrDefault().ToString();                                 
        string myPersistentID = dict.Descendants("key").Where(key => key.Value == "Persistent ID").Select(x => x.NextNode).SingleOrDefault().ToString();

        MyTrackList.Add(new Track
        {
            TrackNumber = myTrackNumber,
            Name = myName,
            PersistentID = myPersistentID
        });

    }
    catch (Exception)
    {
        // Something wasn't set, so skip the node ...
    }            
}
于 2013-01-14T10:07:16.707 回答