hibernate - 休眠标准

Question

Criteria criteria = getSession().createCriteria(clazz); 
Criterion rest1= Restrictions.and(Restrictions.eq("A", "X"), 
       Restrictions.in("B", Arrays.asList("X","Y")));
Criterion rest2= Restrictions.and(Restrictions.eq("A", "Y"), 
       Restrictions.eq("B", "Z"));
criteria.add(Restrictions.or(rest1, rest2));

如果有奇数个 AND 参数，如何创建标准，例如。5?

Answer 1

您可以使用 DetachedCriteria，它看起来像：
Disjunction disjunction = Restrictions.disjunction();
disjunction.add(rest1);
disjunction.add(rest2);
disjunction.add(rest3);
...
dc.add(disjunction);

对于 AND，您可以使用Conjunction而不是Disjunction.

Answer 2

只需将先前调用的结果Restrictions.and()作为 Restrictions.and() 的参数之一

例如：

Criterion cr = Restrictions.and(Restrictions.and(Restrictions.eq("A", "X"), 
       Restrictions.in("B", Arrays.asList("X","Y"))), Restrictions.eq("C", "Z));