6

我有一个 MVC4 页面，它有一个表单，其中包含用作搜索字段的复选框、单选按钮和文本框。发布后，解析选择并使用新结果更新较低的结果网格。现在所有的表单值在返回时都会被清除，新的结果会显示在网格中——只有网格是模型的一部分。

我希望所有表单选择在发布后保留其值，以便用户可以查看（并更改）下一个帖子/搜索的选择。表单填充了 viewbags。

@using (Html.BeginForm("Index", "Home", FormMethod.Post, new { id = "searchform" }))
{
    @Html.ValidationSummary("Please correct the following errors")

<div style="float:left;">

    <div style="float:left;">
    <label>Name:</label>
    @Html.TextBox("name")
    </div>

    <div style="float:left; margin-left:15px">
    <label>Company:</label>
    @Html.TextBox("company")
    </div>

    <div style="float:left; margin-left:65px">
    <label>Date Range:</label>
    @Html.TextBox("dateStart", "", new { @class = "datefield", type = "date" })
    &nbsp;to&nbsp;
    @Html.TextBox("dateEnd", "", new { @class = "datefield", type = "date" })
    </div>

</div>

<div style="clear: both;">
    Match Any Categories? <input type="radio" name="categoryMatchAll" value="false" checked="checked" />&nbsp;&nbsp;&nbsp;
    Match All Categories?  <input type="radio" name="categoryMatchAll" value="true" /> 
</div>

<div style="float:left;">

    <div id="searchform-categories" style="float:left;">
        <div class="scroll_checkboxes">
            <label>Categories</label>
            <ul>
            @foreach (var x in ViewBag.Categories)
            {
                    <li>
                        <input type="checkbox" name="categories" value="@x.Id"/>

                        @x.Name

                    </li>
            }
            </ul>
        </div>
    </div>

    <div id="searchform-diversity" style="float:left; margin-left:30px">    
        <div class="search-selection" style="float:left;">
            <label>Minority Owned</label>
            <ul>
                @foreach (var x in ViewBag.Minorities)
                {
                    <li>
                        @Html.RadioButton("minorities", (String)x.Id.ToString())
                        @x.Name
                    </li>
                }
            </ul>
        </div>
        <div class="search-selection" style="float:left;">
            <label>Diversity Class</label>
            <ul>
            @foreach (var x in ViewBag.Classifications)
            {
                <li>
                    @Html.RadioButton("classifications", (String)x.Id.ToString())
                    @x.Name
                </li>
            }
        </ul>
        </div>    
    </div>  

</div>    

<div style="clear: both;">
    <input type="submit" value="Search Profiles" />
    <input type="submit" value="Reset" />
    </div>       
}

数据网格绑定到模型为

@model IEnumerable<VendorProfileIntranet.Models.VendorProfile>

<table id="VendorTable" width="100%" class="gradeA">
<thead>
    <tr>
    <th>
        @Html.DisplayNameFor(model => model.Name)
    </th>
    <th>
        @Html.DisplayNameFor(model => model.CompanyName)
    </th>
    <th>
        @Html.DisplayNameFor(model => model.City)
    </th>
    <th>
        @Html.DisplayNameFor(model => model.State)
    </th>
    <th>
        @Html.DisplayNameFor(model => model.DateCreated)
    </th>
    <th>Actions</th>
    </tr>
</thead>
<tbody>

@foreach (var item in Model)
{
<tr>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.Name)
    </td>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.CompanyName)
    </td>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.City)
    </td>
    <td>
        @Html.DisplayFor(modelItem => item.State)
    </td>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.DateCreated)
    </td>
    <td class="list-field">
        @Html.ActionLink("Edit", "Edit", new { id = item.ProfileID }) |
        @Html.ActionLink("View", "View", new { id = item.ProfileID }) |
        @Html.ActionLink("Delete", "Delete", new { id = item.ProfileID }, new { onclick = " return DeleteConfirm()" })
    </td>
</tr>

}

</tbody>
<tfoot>
    <tr>
        <td>&nbsp;</td>
    </tr>
</tfoot>

4

3 回答 3

2

如果您在 mvc 中使用 html，请从这里检查解决方案 2，对我来说value="@Request["txtNumber1"]"效果很好，

<input type="text" id="txtNumber1" name="txtNumber1" value="@Request["txtNumber1"]"/>

希望对某人有所帮助。

于 2015-03-30T08:03:11.873 回答
1

我通常做的是将发布的模型传回视图。这样，值不会被清除。

您的代码将如下所示：

<div style="float:left;">

    <div style="float:left;">
    <label>Name:</label>
    @Html.TextBox("name", Model.Name)
    </div>

<div style="float:left; margin-left:15px">
<label>Company:</label>
@Html.TextBox("company", Model.Company)
</div>

<div style="float:left; margin-left:65px">
<label>Date Range:</label>
@Html.TextBox("dateStart", Model.DateStart, new { @class = "datefield", type = "date" })
&nbsp;to&nbsp;
@Html.TextBox("dateEnd", Model.DateEnd, new { @class = "datefield", type = "date" })
</div>

最初获取表单时，您必须创建一个 new Model，否则Model它将为 null 并在对其调用属性时引发异常。

样品模型

public class SearchModel
{

    public SearchModel()
    {
        Results = new List<Result>();
    }

    public string Name {get; set;}  

    public string Company {get; set;}

    public string DateStart {get; set;}

    public string DateEnd {get; set;}

    public List<Result> Results {get; set;}
}


@foreach (var item in Model.Results)
{
<tr>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.Name)
    </td>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.CompanyName)
    </td>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.City)
    </td>
    <td>
        @Html.DisplayFor(modelItem => item.State)
    </td>
    <td class="list-field">
        @Html.DisplayFor(modelItem => item.DateCreated)
    </td>
    <td class="list-field">
        @Html.ActionLink("Edit", "Edit", new { id = item.ProfileID }) |
        @Html.ActionLink("View", "View", new { id = item.ProfileID }) |
        @Html.ActionLink("Delete", "Delete", new { id = item.ProfileID }, new { onclick = " return DeleteConfirm()" })
    </td>
</tr>

}

这是在 MVC 中为视图创建模型的链接。

于 2013-01-08T22:51:44.713 回答
1

所以这就是我通常如何解决这个问题。我的笔记纯粹是我关于在 MVC 项目中命名类以明确其目的的观点（宗教？）。

几个接口来保持它的可扩展性：

// be specific about what type of results, both in the name of the 
// interface and the property needed, you don't want to have overlapping
// properies on your classes, I like suffixing interfaces that are specific
// to a View or Partial View with View
public interface IPersonSearchResultsView
{
   IEnumerable<EFPerson> PersonSearchResults { get; }
}

public interface IPersonSearchCriteriaView
{
  PersonSearchCriteriaModel PersonSearchModel { get; }
}

几节课

// I like suffixing classes that I only use for MVC with Model
public PersonSearchCriteriaModel
{
  public string Name {get; set;}  
  public string Company {get; set;}
  public string DateStart {get; set;}
  public string DateEnd {get; set;}
}

// I like suffixing classes that I used passed to a View/Partial View
// with ViewModel    
public class PersonSearchViewModel : IPersonSearchResultsView, 
                                     IPersonSearchCriteriaView
{
  public IEnumerable<EFPerson> PersonSearchResults { get; set; }
  public PersonSearchCriteriaModel PersonSearchModel { get; set; }
}

现在对于您的控制器，我将以一种允许您将来使用 Ajax 的方式设置它们。

public PersonController : Controller
{
  public ActionResult Search()
  {
    var model = new PersonSearchViewModel();
    // make sure we don't get a null reference exceptions
    model.PersonSearchModel = new PersonSearchCriteriaModel ();
    model.PersonSearchResults = new List<EFPerson>();
    return this.View(model);
  }

  [HttpPost]
  public ActionResult Search(PersonSearchViewModel model)
  {
    model.PersonSearchResults = this.GetPersonResults(model.PersonSearchModel);

    return this.View(model)
  }

  // You could use this for Ajax
  public ActionResult Results(PersonSearchViewModel model)
  {
    model.PersonSearchResults = this.GetPersonResults(model.PersonSearchModel);

    return this.Partial("Partial-SearchResults", model)
  }

  private GetPersonResults(PersonSearchCriteriaModel criteria)
  {
    return DbContext.GetPersonResults(criteria)
  }
}

创建几个局部视图您的视图。

/Views/Person/Partial-SearchCriteria.cshtml

@model IPersonSearchCriteriaView

// the new part is for htmlAttributes, used by Ajax later
@using (Html.BeginForm(..., new { id="searchCriteria" }))
{
  // Here is were the magic is, if you use the @Html.*For(m=>)
  // Methods, they will create names that match the model
  // and you can back back to the same model on Get/Post

  <label>Name:</label>
  @Html.TextBoxFor(m => Model.PersonSearchModel.Name)

  // or let mvc create a working label automagically

  @Html.EditorFor(m => Model.PersonSearchModel.Name)

  // or let mvc create the entire form..

  @Html.EditorFor(m => Model.PersonSearchModel)
}

/Views/Person/Partial-SearchResults.cshtml

@model IPersonSearchResultsView

@foreach (var person in Model.PersonSearchResults )
{
  <tr>
    <td class="list-field">
      @Html.DisplayFor(modelItem => person.Name)
   </td>

   // etc
  </tr>
 }

最后是观点：

/Views/Person/Search.cshtml

@model PersonSearchViewModel 

@Html.Partial("Partial-SearchCriteria", Model)

// easily change the order of these

<div id="searchResults">
@Html.Partial("Partial-SearchResults", Model);
</div>

现在启用 Ajax 非常简单（很简单，但我并不完全正确）：

$.Ajax({
  url: '/Person/Results',
  data: $('#searchCriteria').serialize(),
  success: function(jsonResult)
  {
    $('#searchResults').innerHtml(jsonResult);
  });
于 2013-01-09T01:03:29.190 回答