我正在尝试从 GWT 中的客户端访问 XML 文件。但看起来 sendRequest 方法根本没有被触发。
我可以在浏览器中看到 xml。我需要在服务器端做任何事情吗？
任何帮助表示赞赏。
这是我的代码
String xmlurl = "http://localhost:8888/test.xml";
RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL.encode(xmlurl));
try {
Request request = builder.sendRequest(null, new RequestCallback() {
public void onError(Request request, Throwable exception) {
System.out.println(exception);
}
public void onResponseReceived(Request request, Response response) {
if (200 == response.getStatusCode()) {
System.out.println(response.getText());
} else {
System.out.println(response.getStatusCode());
}
}
});
} catch (RequestException e) {
System.out.println("exception"+e);
}
我也尝试了以下代码，但遇到了同样的问题。开发人员工具显示响应状态为 200 和正确的响应文本。只是，它在代码中不起作用。
String xmlurl = "http://127.0.0.1:8888/test.xml";
httpGetFile(xmlurl, new AsyncCallback<String>() {
public void onFailure(Throwable caught) {
xmlData = "Error";
}
public void onSuccess(String xmlText) {
xmlData = xmlText;
}
});
public static void httpGetFile(final String url, final AsyncCallback<String> callback) {
final RequestBuilder rb = new RequestBuilder(RequestBuilder.GET, url);
rb.setCallback(new RequestCallback() {
public void onResponseReceived(Request request, Response response) {
try {
System.out.println("dafadfdf");
final int responseCode = response.getStatusCode() / 100;
if (url.startsWith("file:/") || (responseCode == 2)) {
callback.onSuccess(response.getText());
} else {
callback.onFailure(new IllegalStateException("HttpError#" + response.getStatusCode() + " - " + response.getStatusText()));
}
} catch (Throwable e) {
callback.onFailure(e);
}
}
public void onError(Request request, Throwable exception) {
callback.onFailure(exception);
}
});
try {
rb.send();
} catch (RequestException e) {
callback.onFailure(e);
}
}