3

我需要帮助构建 Linq 查询。我有这本字典:

var dict = new Dictionary<string, IDictionary<int, double>>  
{  
    { "one", new Dictionary<int, double>  
        {  
            { 1, 2.0 },  
            { 2, 3.0 }  
        }},  
    { "two", new Dictionary<int, double>  
        {  
            { 1, 3.0 },  
            { 2, 4.0 },  
            { 3, 5.0 }  
        }},  
    { "three", new Dictionary<int, double>  
        {  
            { 1, 4.0 },  
            { 2, 5.0}  
        }}  
    };  

我想选择关联值为 3.0 的所有“字符串”/“整数”元组。使用 Foreach 循环,它看起来像:

var res = new Dictionary<string, int>();
foreach (var elem in dict.Select (d => new { S = d.Key, I = d.Value }))
{
    foreach (var val in elem.I)
    {
        if (val.Value == 3.0)
        {
            res.Add(elem.S, val.Key);
        }
    }
}

我正在尝试对单个 Linq 查询执行相同的操作,但没有成功(我不知道如何将键与子查询中的值“连接”)。你会怎么做?

先感谢您!

4

3 回答 3

3

这是另一种丑陋的方法:

var results = from key1 in dict.Keys
              let valueDict = dict[key1]
              from key2 in valueDict.Keys
              where valueDict[key2] == 3d
              select new { Key1 = key1, Key2 = key2 };
于 2013-01-08T17:16:28.260 回答
3

你可以这样做:

var result = dict
    // flatten to 3-value tuple
    .SelectMany(kvp => kvp.Value
        .Select(kvp2 => new // anonymous object
        {
            OuterKey = kvp.Key, // e.g. "one"
            InnerKey = kvp2.Key, // e.g. 1
            InnerValue = kvp2.Value // e.g. 2.0
        })
    ).Where(o => o.InnerValue == 3.0) // limit to the 3.0 value
    .ToDictionary(o => o.OuterKey, o => o.InnerKey)
    ;

SelectMany 将字典扁平化为如下结构:

{ OuterKey = "one", InnerKey = 1, InnerValue = 2.0 },
{ OuterKey = "one", InnerKey = 2, InnerValue = 3.0 },
{ OuterKey = "two", InnerKey = 1, InnerValue = 3.0 },
{ OuterKey = "two", InnerKey = 2, InnerValue = 4.0 },
{ OuterKey = "two", InnerKey = 3, InnerValue = 5.0 },
{ OuterKey = "three", InnerKey = 1, InnerValue = 4.0 },
{ OuterKey = "three", InnerKey = 2, InnerValue = 5.0 }

Where() 将其限制为仅具有 InnerValue = 3.0 的对象:

{ OuterKey = "one", InnerKey = 2, InnerValue = 3.0 },
{ OuterKey = "two", InnerKey = 1, InnerValue = 3.0 }

ToDictionary() 看起来像这样:

{ "one", 2 },
{ "two", 1 }

如果同一外键下可能有多个 3.0,则可以使用 ToLookup() 代替 ToDictionary()。

于 2013-01-08T17:55:38.503 回答
3

这可以解决问题:

var  res = dict
        .Where(outer => outer.Value.Any(inner => inner.Value == 3.0))
        .ToDictionary(outer => outer.Key, outer => outer.Value.First(x=>x.Value == 3.0).Key);

或使代码更通用:

var predicate = new Func<KeyValuePair<int, double>, bool>(inner => inner.Value == 3.0); 
var  res = dict
        .Where(outer => outer.Value.Any(inner => predicate(inner)))
        .ToDictionary(outer => outer.Key, outer => outer.Value.First(inner => predicate(inner)).Key);
于 2013-01-08T17:12:20.463 回答