1

我在使用交叉表的报告中有两个查询的联合。报告的目的是列出与每个日期对应的值。

第一个查询返回与日期对应的值。第二个查询返回剩余日期及其值。

最后，完成了两个查询的联合。许多人可能会建议使用单个查询来实现这一点，但我无法通过使用 LEFT JOIN 的单个查询来做到这一点，因为它不返回 NULL 值。即使我得到了这个工作，我拥有的 GROUP BY 子句将在 iReport 中分成两行.. NON NULLS AND NULLS。

所以，我能想到的唯一方法是使用联合。输出看起来像

      01/01/2013 02/01/2013 03/01/2013 04/01/2013 05/01/2013
X     £120.00    £120.00    £120.00                         
                                       £0.00     £0.00           .

结果两行是由于 GROUP BY.(rowGroup)。日期是列组。理想情况下，我希望它排成一行。

查询是

SELECT
   rates_Booking.date
   rates_Booking.amount,    
   booking.reference    

FROM
   rates_Booking
   LEFT JOIN booking ON booking.reference = rates_Booking.bookingReference                                                                  

   LEFT JOIN unit ON booking.apartment = unit.unit

   LEFT JOIN property ON property.property = unit.property

 WHERE
   rates_Booking.date BETWEEN $P{startDate} AND $P{endDate} 

   AND  $X{IN,property.property,buildings}
   AND  $X{IN,property.area,location}
   AND  $X{IN, unit.unit, unit}

UNION


   SELECT
    rates_Calendar.date
    0.00 as amount,
    '' as reference     

FROM
    rates_Calendar,unit


    LEFT JOIN property ON property.property = unit.property
    LEFT JOIN regions ON regions.region = property.area

    # unit to apartments
    LEFT JOIN apartments ON (apartments.unit = unit.unit)
    LEFT JOIN apartmentTypes ON (apartmentTypes.id = apartments.apartmentTypeId)


WHERE
    rates_Calendar.date BETWEEN $P{startDate} AND $P{endDate}
    AND rates_Calendar.date NOT IN (
                                       SELECT   
                                          rates_Booking.date
                                       FROM                                                                           
                                          rates_Booking                                                                             
                                          LEFT JOIN booking ON booking.reference =   rates_Booking.bookingReference                                 
                                          LEFT JOIN unit ON booking.apartment = unit.unit
                                          LEFT JOIN property ON property.property = unit.property                                                                               

                                          LEFT JOIN apartments ON (apartments.unit =  unit.unit)                                                                                                                         
                                          LEFT JOIN apartmentTypes ON (apartmentTypes.id = apartments.apartmentTypeId)

                                        WHERE                                                                            
                                           rates_Booking.date BETWEEN $P{startDate} AND $P{endDate}                                                                                                                                                         
                                           AND  $X{IN, unit.unit, unit}                                                                                                 
                                           AND  $X{IN, apartmentTypes.id,apartmentType}

                                        GROUP BY

                                           rates_Booking.date



                                            )                                                                                        



    AND $X{IN,property.property,buildings}
    AND $X{IN,property.area,location}
    AND $X{IN, unit.unit, unit}

另外，有人可以建议它不需要UNION。我知道使用子查询不会带来最佳性能。但是在 JOINS 的 ON 子句中使用 WHERE 条件并没有帮助。

4

2 回答 2

1

除了在查询中添加 0.00 值，您还可以将它们添加到交叉表详细信息字段中，修改详细信息/详细信息部分中字段的字段表达式：

$V{amountMeasure} == null ? 0.00 : $V{amountMeasure}

假设这$V{amountMeasure}是基于金额字段生成的度量名称。

于 2013-01-09T11:41:41.987 回答
0 
 SELECT DATE, SUM(AMOUNT)
 FROM (first query UNION second query)
 GROUP BY DATE
 ORDER BY DATE
于 2013-01-08T19:58:43.140 回答