使用带有库分页的 CodeIgniter 框架对表进行编号时遇到问题。下面是表格。。
+------------------------------------------+
| num| NIP | Name | Category | Type |
+------------------------------------------+
| 1 | 12345 | udin | A | A1 |
+------------------------------------------+
| | | | B | B1 |
+------------------------------------------+
| | | | C | C1 |
+------------------------------------------+
| 2 | 54321 | JHON | B | B2 |
+------------------------------------------+
| | | | C | C1 |
+------------------------------------------+
问题在下表的下一页。
+------------------------------------------+
| num| NIP | Name | Category | Type |
+------------------------------------------+
| 1 | 54321 | JHON | F | F2 |
+------------------------------------------+
| | | | G | G3 |
+------------------------------------------+
| | | | G | G4 |
+------------------------------------------+
| | | | I | I3 |
+------------------------------------------+
| | | | J | J1 |
+------------------------------------------+
我想要从前一个值的末尾开始的下一页编号顺序编号。假设在图 2 中编号为“2”而不是“1”。
控制器中的代码:
$this->load->library('pagination');
$data['judul'] = 'Report Data Attachment';
$start_row = $this->uri->segment(3);
$per_page = 10;
if (trim($this->uri->segment(3)) == '')
{
$start_row = '0';
}
$config['base_url'] = base_url().'report/index/';
$config['total_rows'] = $this->lampiran_m->lampiran_karyawan_semua_page_conter()->num_rows();
//$config['uri_segment'] = '3';
$config['per_page'] = $per_page;
$config['full_tag_open'] = '<p class="page">';
$config['full_tag_close'] = '</p>';
$this->pagination->initialize($config);
$data['pagination'] = $this->pagination->create_links();
$data['lampiran'] = $this->lampiran_m->lampiran_karyawan_semua_page($start_row,','.$per_page);
$data['no'] = '';
$data['last'] = '';
$this->template->display('tabel_report',$data);
和我的模型中的代码:
public function lampiran_karyawan_semua_page($offset='',$limit='')
{
$qry = "select distinct lampiran.id_category,name_category,tipe,lampiran.nip from lampiran
left join employee on (lampiran.nip = employee.nip)
left join category on (lampiran.id_category=category.id_category) where lampiran.id_category = category.id_category and lampiran.nip=employee.nip order by lampiran.nip desc limit $offset $limit";
return $this->db->query($qry);
}
并查看此代码:
<table border="1" width="100%" cellpadding="0" cellspacing="0" id="product-table" >
<tr>
<th class="table-header-repeat line-left minwidth-1"> <a href="#mainform">No</a></th>
<th class="table-header-repeat line-left minwidth-1"> <a href="#mainform">NIP</a></th>
<th class="table-header-repeat line-left minwidth-1"> <a href="#mainform">Name</a></th>
<th class="table-header-repeat line-left minwidth-1"> <a href="#mainform">Category Attachment</a></th>
<th class="table-header-repeat line-left minwidth-1"><a href="#mainform">Type Attachment</a> </th>
<th class="table-header-repeat line-left minwidth-1"><a href="#mainform">Page</a> </th>
</tr>
<?php
foreach($lampiran->result_array() as $k) {
$now=$k['nip'];
if($last!=$now ) {
$no++;
echo "<tr><td>$no</td><td>$k[nip]</td><td>".$this->employee_m->get($k['nip'])->nama."</td><td>$k[name_category]</td><td>$k[tipe]</td><td>"; ?>
<?php foreach($this->lampiran_m->conter_tabel_semua($k['id_category'],$k['tipe'],$k['nip'])->result() as $row) :?>
<?php echo $row->nilai;?>
<?php endforeach;
echo "</td></tr>";
}else{
echo "<tr><td> </td><td> </td><td> </td><td>$k[name_category]</td><td>$k[tipe]</td><td>"; ?>
<?php foreach($this->lampiran_m->conter_tabel_semua($k['id_category'],$k['tipe'],$k['nip'])->result() as $row) :?>
<?php echo $row->nilai;?>
<?php endforeach;
echo "</td></tr>";
}
$last = $k['nip'];
}
?>
<tr><td colspan="5" style="text-align: center;"><b>Jumlah Total</b></td><td>
<?php foreach($this->lampiran_m->jumlah_semua_lampiran()->result() as $row) :?>
<?php echo "<b>$row->jumlah</b>";?>
<?php endforeach; ?>
</td></tr>
</table>
我希望有人可以在这个问题上帮助我..谢谢