我正在创建一个函数，在插入用户名后将从数据库中检索用户显示图片。但我的代码遇到了一些问题。请帮我检查一下^^非常感谢。
<?php
include("connection.php");
$name = $_SESSION['login_username']; // login_username is test123, this is $_SESSION from another .php file
$_SESSION['name'] = $storename;
echo '<img src="display2.php"width="90" height="90"/>'; //this is how i display my picture
?>
Display.php（不工作）
mysql_select_db($database) or die("Can not select the database: ".mysql_error());
$storename = $_SESSION['name']; // is there an error with my $_session statement?
$name = (string)$storename;
if(!isset($name) || empty($name)){
die("Please select your image!");
}else{
$query = mysql_query("SELECT * FROM customerdetail WHERE customer_username='$name'");
$num_row = mysql_fetch_array($query);
$content = $num_row['image'];
header('Content-type: image/jpg');
echo $content;
}
}
Display.php（工作）
$storename = "test123"; // it worked if i store the id in string but not passing from another page.
$name = (string)$storename;
if(!isset($name) || empty($name)){
die("Please select your image!");
}else{
$query = mysql_query("SELECT * FROM customerdetail WHERE customer_username='$name'");
$row = mysql_fetch_array($query);
$content = $row['image'];
header('Content-type: image/jpg');
echo $content;
}
?>
谁能帮我弄清楚出了什么问题？提前致谢。