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我正在制作宾果卡生成器以尝试了解有关 WPF 的更多信息，并且无法弄清楚如何设置标签内容属性以从我的代码隐藏文件中的属性中设置。

我以为我可以使用

<Setter Property="Content" Value="{Binding BNumber}">

对于 content 属性，将标签的内容设置为 my 的随机元素List<String>？

我的MainWindow.xaml中有

<Window x:Class="Bingo.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="600" Width="800"
        WindowStartupLocation="CenterScreen">
  <Grid>
    <Grid Width="350" Height="420" ShowGridLines="True">
      <Grid.RowDefinitions>
        <RowDefinition Height="70"/>
        <RowDefinition Height="70"/>
        <RowDefinition Height="70"/>
        <RowDefinition Height="70"/>
        <RowDefinition Height="70"/>
        <RowDefinition Height="70"/>
      </Grid.RowDefinitions>
      <Grid.ColumnDefinitions>
        <ColumnDefinition Width="70" />
        <ColumnDefinition Width="70" />
        <ColumnDefinition Width="70" />
        <ColumnDefinition Width="70" />
        <ColumnDefinition Width="70" />
      </Grid.ColumnDefinitions>
      <!-- The Label I'm trying to set in this example -->
      <Label Grid.Column="0" Grid.Row="1" Style="{StaticResource BNumber}"
             FontSize="50" Width="70"/>
    </Grid>
  </Grid>
</Window>

我的App.xaml代码

<Application x:Class="Bingo.App"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             StartupUri="MainWindow.xaml">
  <Application.Resources>
    <Style TargetType="Label" x:Key="BNumber">
      <Setter Property="Content" Value="{Binding}"></Setter>
      <Setter Property="Background">
        <Setter.Value>
          <SolidColorBrush Color="Beige"/>
        </Setter.Value>
      </Setter>
    </Style>
  </Application.Resources>
</Application>

在我的MainWindow.xaml.cs我有这个List<String> BNumbers对象和一个返回BNumbers列表的随机元素的属性

public MainWindow() {
  InitializeComponent();
  BNumbers.Add("1");
  BNumbers.Add("2");
  BNumbers.Add("3");
  BNumbers.Add("4");
  BNumbers.Add("5");
  BNumbers.Add("6");
  BNumbers.Add("7");
  BNumbers.Add("8");
  BNumbers.Add("9");
  BNumbers.Add("10");
  BNumbers.Add("11");
  BNumbers.Add("12");
  BNumbers.Add("13");
  BNumbers.Add("14");
  BNumbers.Add("15");
}
public string RandomBNumber {
  get { return randomB(); }
}
public string randomB() {
  Random rand = new Random();
  int randomBNumber = rand.Next(0, 15);
  return BNumbers[randomBNumber];
}
public List<String> BNumbers = new List<string>();
4

2 回答 2

3

随机化列表本身然后每个数字可能更容易，因为这将停止重复。

Aslo 使用统一网格可能比添加一堆标签更容易。

例子：

xml:

<Window x:Class="WpfApplication4.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="346" Width="300" Name="UI">

    <Grid DataContext="{Binding ElementName=UI}">
        <ItemsControl ItemsSource="{Binding BNumbers}" Margin="0,29,0,0">
            <ItemsControl.ItemTemplate>
                <DataTemplate>
                    <Border Margin="1" BorderBrush="Black" BorderThickness="1" CornerRadius="2">
                         <Label Content="{Binding}" HorizontalContentAlignment="Center" VerticalContentAlignment="Center"  />
                    </Border>
                </DataTemplate>
            </ItemsControl.ItemTemplate>
            <ItemsControl.ItemsPanel>
                <ItemsPanelTemplate>
                    <UniformGrid Columns="5" Rows="5"/>
                </ItemsPanelTemplate>
            </ItemsControl.ItemsPanel>
        </ItemsControl>
        <Button Content="New" Height="23" HorizontalAlignment="Left" Name="button1" VerticalAlignment="Top" Width="75" Click="button1_Click" />
    </Grid>
 </Window>

代码：

public partial class MainWindow : Window, INotifyPropertyChanged
{
    public List<string> AllNumbers { get; set; }
    private List<string> _bnumbers = new List<string>();

    public MainWindow()
    {
        InitializeComponent();
        AllNumbers = new List<string>();
        // Bingo game 75 numbers, 5x5 grid
        for (int i = 0; i < 75; i++)
        {
            AllNumbers.Add(i.ToString());
        }
    }

    public List<string> BNumbers
    {
        get { return _bnumbers; }
        set { _bnumbers = value; NotifyPropertyChanged("BNumbers"); }
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        RandomizeList(AllNumbers);
        BNumbers = AllNumbers.Take(25).ToList();
    }

    private void RandomizeList<T>(IList<T> list)
    {
        Random rng = new Random();
        int n = list.Count;
        while (n > 1)
        {
            n--;
            int k = rng.Next(n + 1);
            T value = list[k];
            list[k] = list[n];
            list[n] = value;
        }
    }

    public event PropertyChangedEventHandler PropertyChanged;
    private void NotifyPropertyChanged(string property)
    {
        if (PropertyChanged != null)
        {
            PropertyChanged(this, new PropertyChangedEventArgs(property));
        }
    }
}

结果（“New”将生成一个新游戏）

在此处输入图像描述

于 2013-01-07T23:18:59.817 回答
2

在构造函数中，您需要设置 DataContext：

this.DataContext = this;

您还需要更改您的设置器以匹配属性名称 RandomBNumber ：

<Setter Property="Content" Value="{Binding RandomBNumber }">
于 2013-01-07T22:42:48.780 回答