mysql - 如何将同一张表的两个查询放在一起

Question

我无法将两个查询合二为一。

查询1：

SELECT *
FROM (`text`)
WHERE `text` LIKE '%TERM1%' ORDER BY `text`.`start` DESC

查询2：

SELECT *,
  MATCH (col1,  col2,  col3) AGAINST ('%TERM2%' IN BOOLEAN MODE) AS relevance
FROM `text`
WHERE MATCH (col1, col2, col3) AGAINST ('%TERM2%' IN BOOLEAN MODE)
      AND status=2
ORDER BY `text`.`start` DESC

任何建议都会被接受。

表“文本”看起来像

+-------+--------+-------+------+------+
|  col1 |  col2  | col3  | text |  id  |
+-------+--------+-------+------+------+
| name1 | place1 | date1 | val1 |   1  |
| name2 | place2 | date2 | val2 |   2  |
| name3 | place2 | date5 | val1 |   3  |
| name4 | place4 | date4 | val5 |   4  |
| name5 | place5 | date5 | val5 |   5  |
:
:
| namex | placex | datex | valx |   x  |
+-------+--------+-------+------+------+

我忘了写，第一个查询也必须按开始 DESC 排序...

我期望结果如下：term1 = val1，term2 = val5

+-------+--------+-------+------+------+
|  col1 |  col2  | col3  | text |  id  |
+-------+--------+-------+------+------+

qery1 结果：

| name3 | place2 | date5 | val1 |   3  |
| name1 | place1 | date1 | val1 |   1  |

查询2结果

| name5 | place5 | date5 | val5 |   5  |
| name4 | place4 | date4 | val5 |   4  |
:
:
| namex | placex | datex | valx |   1  |
+-------+--------+-------+------+------+

谢谢。

@PinnyM - 是的表被命名text并且在表立场列内text，不幸的是，我采用了具有完整数据库的项目，这很荒谬，但因为有必要或不需要更改表名，所以更改完整代码也是荒谬的。

Answer 1

这是一种方式：

SELECT t.*, -1 as relevance
FROM `text` t
WHERE `text` LIKE '%TERM1%'
union all
SELECT t.*, MATCH (col1,  col2,  col3) AGAINST ('%TERM2%' IN BOOLEAN MODE) AS relevance
FROM `text` t
WHERE MATCH (col1, col2, col3) AGAINST ('%TERM2%' IN BOOLEAN MODE) AND status=2
ORDER BY `text`.`start` DESC