sql - Sql Server MAX of sum(Amount)

Question

我有一张表格，其中有客户制作的付款详细信息。列如下：

ID, ClientID, Amount

现在我想通过客户 ID 找到 5 个最大金额组。

我找到DENSE_RANK()了，但它不适合我，因为我想找到sum of amount。

谢谢。

Answer 1

请试试：

SELECT 
    ClientID, 
SUM(Amount) Amount 
FROM(
    SELECT ROW_NUMBER() OVER (PARTITION BY ClientID ORDER BY Amount DESC) DR, 
        ClientID, 
        Amount 
    FROM YourTable
)x WHERE x.DR<=5
GROUP BY ClientID
ORDER BY ClientID

Answer 2

;WITH totalSum
AS
(
    SELECT  ClientID, SUM(Amount) totalAmount
    FROM    tableName
    GROUP   BY ClientID
)
SELECT ClientID, totalAmount
FROM
    (
        SELECT  ClientID, totalAmount,
                DENSE_RANK() OVER (ORDER BY totalAmount DESC) rn
        FROM    totalSum
    ) s
WHERE   rn <= 5

Answer 3

SELECT 
    ID,
    ClientID,
    Amount
FROM
    PaymentDetails
GROUP BY
    ID
HAVING
   Amount = SUM(Amount)

Answer 4

这对你有用吗？（不确定我是否理解您的问题）如果您想要 TOP 5 的总数，就是这样。SUM()查找每个客户的TOP 5金额的查询是不同的。

;WITH OrderingCTE AS
(
    SELECT   ID
            ,ClientID
            ,Amount = SUM(Amount)
            ,rNum   = ROW_NUMBER() OVER (PARTITION BY ClientID ORDER BY SUM(Amount) DESC)
    FROM MyTable
    GROUP BY ID
            ,ClientID
)
SELECT *
FROM OrderingCTE
WHERE rNum <=5