mysql - MySQL - 如何按组汇总计数

Question

我有三个与以下关系相关的表：

"agency" 1-n "agent" 1-n "ad" 
(agency has many agents and each agent has many ads)

我想按代理商获取广告计数列表，如下所示：

agency_name   |   ad_count
---------------------------
agency 1      |     15
agency 2      |     25
agency 3      |     0

甚至会显示 0 个广告的代理机构。这可能吗？非常感谢！

Answer 1

由于您没有提供确切的表结构，我不得不猜测一下

select agency.agency_name, 
       count(ad.id) as ad_count
from agency 
left outer join agent on agency.id = agent.agency_id
left outer join ad on ad.id = agent.ad_id
group by agency.agency_name

Answer 2

SQL小提琴

select agency.agency_name, count(ad.id)
from agency
left join agent on agent.agency_id = agency.id
left join ad on ad.agent_id = agent.id
group by agency.agency_name

Answer 3

试试这个：

SELECT a.agencyname, IFNULL(b.adcnt, 0) adcount  
FROM agency 
LEFT JOIN (SELECT a.agencyid, SUM(adcnt) adcnt 
           FROM agent a 
           INNER JOIN (SELECT agentid, COUNT(agentid) adcnt 
                       FROM ad 
                       GROUP BY agentid
                      ) b ON a.agentid = b.agentid 
           GROUP BY agencyid) b ON a.agencyid = b.agencyid