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我想SELECT id, some_complex_calculations FROM some_table然后更新some_table以插入some_complex_calculations具有适当 ID 的其他列。我该怎么做?

4

2 回答 2

1

尝试这个:

UPDATE some_table 
SET other_column = some_complex_calculations 
WHERE Id = 5; #appropiate ID
于 2013-01-05T18:51:50.117 回答
0

如果我理解您的要求,那么这就是您想要的,UPDATE 将替换现有行。但是你想插入行我猜,

INSERT INTO SOME_TABLE(YOUR_OTHER_COLUMN) 
VALUES(SELECT some_complex_calculations FROM some_table WHERE ID=4) #For Example
于 2013-01-05T19:02:12.063 回答