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我在使用 ruby​​XL 构建的爬虫时遇到问题。它正确地遍历我的文件系统，但我收到一个(Errno::ENOENT)错误。我检查了所有的 ruby​​XL 代码，一切似乎都检查了。我的代码附在下面 - 有什么建议吗？ 

/Users/.../testdata.xlsx
/Users/.../moretestdata.xlsx
/Users/.../Lab 1 Data.xlsx
/Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:404:in `initialize': No such file or directory - /Users/Dylan/.../sheet6.xml (Errno::ENOENT)
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:404:in `open'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:404:in `block in decompress'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:402:in `upto'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:402:in `decompress'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:47:in `parse'
    from xlcrawler.rb:9:in `block in xlcrawler'
    from /Users/Dylan/.rvm/rubies/ruby-1.9.3-p327/lib/ruby/1.9.1/find.rb:41:in `block in find'
    from /Users/Dylan/.rvm/rubies/ruby-1.9.3-p327/lib/ruby/1.9.1/find.rb:40:in `catch'
    from /Users/Dylan/.rvm/rubies/ruby-1.9.3-p327/lib/ruby/1.9.1/find.rb:40:in `find'
    from xlcrawler.rb:6:in `xlcrawler'
    from xlcrawler.rb:22:in `<main>'

require 'find'
require 'rubyXL'

def xlcrawler(path)
  count = 0
  Find.find(path) do |file|                                # begin iteration of each file of a specified directory
    if file =~ /\b.xlsx$\b/                                # check if a given file is xlsx format
      puts file                                            # ensure crawler is traversing the file system
      workbook = RubyXL::Parser.parse(file).worksheets     # creates an object containing all worksheets of an excel workbook
      workbook.each do |worksheet|                         # begin iteration over each worksheet
        data = worksheet.extract_data.to_s                 # extract data of a given worksheet - must be converted to a string in order to match a regex
        if data =~ /regex/
          puts file
          count += 1
        end      
      end
    end
  end
  puts "#{count} files were found"
end

xlcrawler('/Users/')
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1 回答 1

2

我对 github 上的 ruby​​XL 代码进行了一些挖掘，看起来解压缩方法中存在错误。

  files['styles'] = Nokogiri::XML.parse(File.open(File.join(dir_path,'xl','styles.xml'),'r'))
  @num_sheets = files['workbook'].css('sheets').children.size
  @num_sheets = Integer(@num_sheets)

  #adds all worksheet xml files to files hash
  i=1
  1.upto(@num_sheets) do
    filename = 'sheet'+i.to_s # <----- BUG IS HERE
    files[i] = Nokogiri::XML.parse(File.open(File.join(dir_path,'xl','worksheets',filename+'.xml'),'r'))
    i=i+1
  end

这段代码对 excel 中的工作表编号做了一个假设，这是不正确的。此代码只是计算纸张的数量，并以数字方式分配它们。但是，如果您删除一个工作表然后创建一个新工作表，则数字序列会被破坏。

如果你检查你的Lab Data 1.xlsx文件，你会看到没有 sheet6，如果你打开 vba 开发者窗口（按 alt + F11）你应该看到类似

工作表列表

如您所见，这种安排将破坏 for 循环并在 i = 6 时导致异常。

于 2013-01-06T05:06:00.040 回答