1

我有这样的表：

<table class="content">
<tbody>
   <tr class="fc-first">

      <td class="fc-widget-content fc-day0 fc-first">
    <div>
        <div class="fc-day-number">1</div>
        <div class="fc-day-content">
            <div style="position:relative"> </div>
        </div>
    </div>
      </td>
      <td class="fc-widget-content fc-day1">
    <div>
        <div class="fc-day-number">2</div>
        <div class="fc-day-content">
            <div style="position:relative"> </div>
        </div>
    </div>
      </td>
      <td class="fc-widget-content fc-day2">
    <div>
        <div class="fc-day-number">3</div>
        <div class="fc-day-content">
            <div style="position:relative"> </div>
        </div>
    </div>
      </td>
   </tr>
   <tr class="fc-week1"></tr>
   <tr class="fc-week2"></tr>
</tbody>
</table>

并且我想添加 CSS 类以仅基于 到目前为止td包含我的 jquery 代码的内容：<div> class"fc-day-number">2</div>

var content_td;
var content = $('.content' );
content_td = content.find('td');

我以为我可以使用嵌套查找，但不知道如何。

4

2 回答 2

2

你需要的是.closest()方法

$('table.content td[class="fc-day-number"]').closest('td').addClass('SOME_CLASS');

和你的固定 HTML

<table class="content">
<tbody>

   <tr class="fc-first">

    <td class="fc-widget-content fc-day0 fc-first">
      <div>
        <div class="fc-day-number">1</div>
        <div class="fc-day-content">
            <div style="position:relative"> </div>
        </div>
      </div>
    </td>
    <td class="fc-widget-content fc-day1">
      <div>
        <div class="fc-day-number">2</div>
        <div class="fc-day-content">
            <div style="position:relative"> </div>
        </div>
      </div>
    </td>
    <td class="fc-widget-content fc-day2">
      <div>
        <div class="fc-day-number">3</div>
        <div class="fc-day-content">
            <div style="position:relative"> </div>
        </div>
      </div>
    </td>

   </tr>

   <tr class="fc-week1"></tr>
   <tr class="fc-week2"></tr>

</tbody>
</table>
于 2013-01-05T10:26:05.103 回答
1

确保引用类选择器，使其成为字符串文字。另外，将 content_td 设为变量。

var content = $(".content"); //Quotes added
var content_td = content.find('td');
于 2013-01-05T10:12:43.117 回答