0

我有一个循环遍历数据的正则表达式，如下所示

23:10:54 User Name 1 has looted 598 x Dark Ochre
23:13:58 UserName 2 has looted 947 x Obsidian Ochre
22:55:29 User Name3 has looted 1509 x Onyx Ochre
22:55:29 User Name3 has looted 3 x Obsidian Ochre

正则表达式（下）正确地将数据解析为值$value['userName'];

$re = '/^(?<timeMined>[0-9]{2}:[0-9]{2}:[0-9]{2}) # timeMined 
     \s+
     (?<userName>[\w\s]+)        # user name
     \s+(?:has\s+looted)\s+    # garbage text between name and amount
     (?<amount>\d+)              # amount
     \s+x\s+                     # multiplication symbol
     (?<item>.*?)\s*$            # item name (to end of line)
   /xmu';
preg_match_all($re, $sample, $matches, PREG_SET_ORDER);

在下面的数据集中，有 3 个不同的用户名。我正在尝试遍历数据并将用户名添加到数组中（如果它尚不存在）。这是我目前拥有的。但是，我只得到 1 个结果，用户名 3。我对问题出在哪里感到困惑。

foreach ($matches as $value){
  $userName = $value['userName'];
  echo $userName."<BR>";
  $userNameArray = array();
  if (in_array($userName, $userNameArray)){
  }
  else {
    array_push($userNameArray, $userName);
  }
}
echo "<BR><BR><BR><BR><BR>";
foreach ($userNameArray as $value){
  echo $value."<BR>";
}

此代码导致以下结果。顶部是准确的，但是底部缺少两个用户名

User Name 1
UserName 2
User Name3
User Name3






User Name3
4

1 回答 1

1

你在每次迭代的 for 循环中删除你的数组；）

foreach ($matches as $value){
  $userName = $value['userName'];
  echo $userName."<BR>";
  $userNameArray = array(); // resetting the array each time...
  if (in_array($userName, $userNameArray)){
  }
  else {
    array_push($userNameArray, $userName);
  }
}
于 2013-01-04T22:10:27.823 回答