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你们中的任何一个 symfony2 大师都可以告诉我如何从 symfony2 服务中写一个 flash 消息吗？

当我如下注入容器时，我以为我有我需要的东西，但显然没有，我收到错误

Fatal error: Call to undefined method appDevDebugProjectContainer::getRequest() in /var/www/cloudsign_beta/src/BizTV/CommonBundle/Helper/globalHelper.php on line 135

所以显然我无法访问请求......如果我也必须从控制器传递它，我很快就会失去服务的意义，它本身无法做任何事情=）

<?php
namespace BizTV\CommonBundle\Helper;

use Symfony\Component\DependencyInjection\ContainerInterface as Container;
use Doctrine\ORM\EntityManager as EntityManager;

use BizTV\CommonBundle\Entity\Log;

class globalHelper {    

    private $container;
    private $em;

    public function __construct(Container $container, EntityManager $em) {
        $this->container = $container;
        $this->em = $em;
    }

    public function log($type,$message) {

        // currently $type can be 'success', 'fail' or 'error'.

        $currentUser = $this->container->get('security.context')->getToken()->getUser();
        $currentCompany = $this->container->get('security.context')->getToken()->getUser()->getCompany();

        //if the $type is one that we want to write to the log then create log entity (we don't log failed attempts at operations, but we do log errors.
        if ($type == 'success') {
            $em = $this->em;
            $now = new \DateTime("now");

            $entity  = new Log();
            $entity->setCompany($currentCompany);
            $entity->setExecutor($currentUser);
            $entity->setTime($now);
            $entity->setEventType($type);
            $entity->setEventMessage($message);

            $em->persist($entity);
            $em->flush();
        }

        //flash out the $message message text
        $container = $this->container;
        $session = $container->getRequest()->getSession()->setFlash($type, $message);

    }

}
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1 回答 1

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$session = $container->get('request')->getSession()->setFlash($type, $message);

但要小心，因为您可能不知道是否request存在。管理此问题的正确方法是将您的服务限制在request范围内。

于 2013-01-04T14:58:34.410 回答